# IntegrationWatch

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#1
can anybody help find the definate integral of f(x)=e^(-nx) from 0 to n?
thanks guys
0
5 years ago
#2
(Original post by stanners 27)
can anybody help find the definate integral of f(x)=e^(-nx) from 0 to n?
thanks guys
0
#3
(Original post by Mr M)
So that gives (-e^-n2)/n between 0 and n. but then you have to divide by 0.
0
5 years ago
#4
(Original post by stanners 27)
So that gives (-e^-n2)/n between 0 and n. but then you have to divide by 0.
What? I think you misunderstood.
0
5 years ago
#5
(Original post by stanners 27)
So that gives (-e^-n2)/n between 0 and n. but then you have to divide by 0.
x is zero not n.
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#6
(Original post by Mr M)
x is zero not n.
you have to divide by x, as that is in the indefinateintegral. then replace x with the boundries. Don't you?
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#7
(Original post by Mr M)
x is zero not n.
ahh i see now. i was confused by x and n. thanks.
0
5 years ago
#8
(Original post by stanners 27)
you have to divide by x, as that is in the indefinateintegral. then replace x with the boundries. Don't you?
No you don't divide by x at any point. Look at my first post carefully. And it's "definite".
0
5 years ago
#9
(Original post by stanners 27)
ahh i see now. i was confused by x and n. thanks.
It's a fairly common mistake to make if that makes you feel any better!
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#10
(Original post by Mr M)
It's a fairly common mistake to make if that makes you feel any better!
Thanks. I don't suppose you know how to calculate infimum of f(x)=(x^0.5)/
(2+x) do you?
0
5 years ago
#11
(Original post by stanners 27)
Thanks. I don't suppose you know how to calculate infimum of f(x)=(x^0.5)/
(2+x) do you?
You could sketch the graph.
0
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