Maths help please :D Watch

theJdog
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I want to know how to work this out fellow mathematicians! Please help and give me the working out method as well please (i have the answer, but i want to know how to get to that answer). Thanks!

The question is: write a as a^n and state the value of n:

√a^8/3

Thanks again!!!!
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Notnek
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(Original post by theJdog)
I want to know how to work this out fellow mathematicians! Please help and give me the working out method as well please (i have the answer, but i want to know how to get to that answer). Thanks!

The question is: write a as a^n and state the value of n:

√a^8/3

Thanks again!!!!
Is that \displaystyle \sqrt{\frac{a^8}{3}}, \displaystyle \frac{\sqrt{a^8}}{3} or something else?

Also, your question doesn't make complete sense. Can you check that you posted it correctly?
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theJdog
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(Original post by notnek)
Is that \displaystyle \sqrt{\frac{a^8}{3}}, \displaystyle \frac{\sqrt{a^8}}{3} or something else?

Also, your question doesn't make complete sense. Can you check that you posted it correctly?
No, it is a fractional indices (so 8/3 is a fractional indices).
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jameswhughes
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(Original post by notnek)
Is that \displaystyle \sqrt{\frac{a^8}{3}}, \displaystyle \frac{\sqrt{a^8}}{3} or something else?

Also, your question doesn't make complete sense. Can you check that you posted it correctly?
I think it's supposed to be (\sqrt a)^{\frac{8}{3}}

OP-try rewriting \sqrt a=a^{\frac{1}{2}}, then you might see it.
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Notnek
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(Original post by theJdog)
No, it is a fractional indices (so 8/3 is a fractional indices).
OK - please use brackets in future.

\displaystyle \sqrt{a^{\frac{8}{3}}} = \left(a^\frac{8}{3}\right)^\frac  {1}{2}

Now use the index law \displaystyle \left(a^b\right)^c = a^{b \times c}

EDIT: The poster above has given a similar method if the question isn't as I have assumed.
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Kvothe the Arcane
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(Original post by theJdog)
No, it is a fractional indices (so 8/3 is a fractional indices).
\displaystyle \sqrt{a^\frac{8}{3}}?
Edit: already beaten
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theJdog
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(Original post by notnek)
Is that \displaystyle \sqrt{\frac{a^8}{3}}, \displaystyle \frac{\sqrt{a^8}}{3} or something else?

Also, your question doesn't make complete sense. Can you check that you posted it correctly?
And the question is: express the following in the form a^n, stating the value of n.
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lubus
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(Original post by theJdog)
No, it is a fractional indices (so 8/3 is a fractional indices).
to avoid ambiguity, write it as (a^(8/2))^(1/2)

Anyway, used the indice rules and you should get it should be straighforward. Remember that square root is also ^(1/2)
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cimuuGuitar
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√a^8/3
=
a^8/3-2
= a^2 2/3-2
= a^2/3

i dont know its true or false
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theJdog
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(Original post by notnek)
OK - please use brackets in future.

\displaystyle \sqrt{a^{\frac{8}{3}}} = \left(a^\frac{8}{3}\right)^\frac  {1}{2}

Now use the index law \displaystyle \left(a^b\right)^c = a^{b \times c}

EDIT: The poster above has given a similar method if the question isn't as I have assumed.
I did that and i got a^2/3, but apparently that's wrong and it should be 1/3 instead :confused:
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theJdog
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(Original post by cimuuGuitar)
√a^8/3
=
a^8/3-2
= a^2 2/3-2
= a^2/3

i dont know its true or false
It's apparently false.
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Notnek
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(Original post by theJdog)
I did that and i got a^2/3, but apparently that's wrong and it should be 1/3 instead :confused:
It's not 2/3 or 1/3:

\displaystyle \frac{8}{3}\times \frac{1}{2} = \frac{8}{6}=\frac{4}{3}
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theJdog
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(Original post by notnek)
It's not 2/3 or 1/3:

\displaystyle \frac{8}{3}\times \frac{1}{2} = \frac{8}{6}=\frac{4}{3}
Sorry i meant that do you think that the answer is a typo?????
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Notnek
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(Original post by theJdog)
Sorry i meant that do you think that the answer is a typo?????
If the question I posted is exactly the same as the one you see in your book then there is a typo in the answer.
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theJdog
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(Original post by notnek)
If the question I posted is exactly the same as the one you see in your book then there is a typo in the answer.
Ok thanks! And yeah i typed it word for word.
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