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#1
I want to know how to work this out fellow mathematicians! Please help and give me the working out method as well please (i have the answer, but i want to know how to get to that answer). Thanks!

The question is: write a as a^n and state the value of n:

√a^8/3

Thanks again!!!!
0
5 years ago
#2
(Original post by theJdog)
I want to know how to work this out fellow mathematicians! Please help and give me the working out method as well please (i have the answer, but i want to know how to get to that answer). Thanks!

The question is: write a as a^n and state the value of n:

√a^8/3

Thanks again!!!!
Is that , or something else?

Also, your question doesn't make complete sense. Can you check that you posted it correctly?
1
#3
(Original post by notnek)
Is that , or something else?

Also, your question doesn't make complete sense. Can you check that you posted it correctly?
No, it is a fractional indices (so 8/3 is a fractional indices).
0
5 years ago
#4
(Original post by notnek)
Is that , or something else?

Also, your question doesn't make complete sense. Can you check that you posted it correctly?
I think it's supposed to be

OP-try rewriting , then you might see it.
0
5 years ago
#5
(Original post by theJdog)
No, it is a fractional indices (so 8/3 is a fractional indices).
OK - please use brackets in future.

Now use the index law

EDIT: The poster above has given a similar method if the question isn't as I have assumed.
0
5 years ago
#6
(Original post by theJdog)
No, it is a fractional indices (so 8/3 is a fractional indices).
?
0
#7
(Original post by notnek)
Is that , or something else?

Also, your question doesn't make complete sense. Can you check that you posted it correctly?
And the question is: express the following in the form a^n, stating the value of n.
0
5 years ago
#8
(Original post by theJdog)
No, it is a fractional indices (so 8/3 is a fractional indices).
to avoid ambiguity, write it as (a^(8/2))^(1/2)

Anyway, used the indice rules and you should get it should be straighforward. Remember that square root is also ^(1/2)
0
5 years ago
#9
√a^8/3
=
a^8/3-2
= a^2 2/3-2
= a^2/3

i dont know its true or false
0
#10
(Original post by notnek)
OK - please use brackets in future.

Now use the index law

EDIT: The poster above has given a similar method if the question isn't as I have assumed.
I did that and i got a^2/3, but apparently that's wrong and it should be 1/3 instead
0
#11
(Original post by cimuuGuitar)
√a^8/3
=
a^8/3-2
= a^2 2/3-2
= a^2/3

i dont know its true or false
It's apparently false.
0
5 years ago
#12
(Original post by theJdog)
I did that and i got a^2/3, but apparently that's wrong and it should be 1/3 instead
It's not 2/3 or 1/3:

0
#13
(Original post by notnek)
It's not 2/3 or 1/3:

Sorry i meant that do you think that the answer is a typo?????
0
5 years ago
#14
(Original post by theJdog)
Sorry i meant that do you think that the answer is a typo?????
If the question I posted is exactly the same as the one you see in your book then there is a typo in the answer.
0
#15
(Original post by notnek)
If the question I posted is exactly the same as the one you see in your book then there is a typo in the answer.
Ok thanks! And yeah i typed it word for word.
0
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