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    I asked this on another forum :

    http://vvcap.net/db/eK8poiQurF4YgAacDpkm.htp

    and someone answered my question with:

    http://vvcap.net/db/Tx39N5Xd6IpSsvAE711g.htp

    Could someone please explain to me in basic terms how this answer was solved?

    I understand it partially but i don't understand why e.g. 3^2 is continuing throughout the sequence =/
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    (Original post by Maths94)
    I asked this on another forum :

    http://vvcap.net/db/eK8poiQurF4YgAacDpkm.htp

    and someone answered my question with:

    http://vvcap.net/db/Tx39N5Xd6IpSsvAE711g.htp

    Could someone please explain to me in basic terms how this answer was solved?

    I understand it partially but i don't understand why e.g. 3^2 is continuing throughout the sequence =/
    The recursive formula:
    f(0)=0
    f(x)=x^2+f(x-1)
    So
    f(1)=1^2+f(0)=1+0=1
    f(2)=2^2+f(1)=4+1=5
    f(3)=3^2+f(2)=9+5=14

    or you can write
    f(3)=3^2+f(2)=3^2+2^2+f(1)=3^2+2  ^2+1^1+f(0)=9+4+1+0=14
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    (Original post by ztibor)
    The recursive formula:
    f(0)=0
    f(x)=x^2+f(x-1)
    So
    f(1)=1^2+f(0)=1+0=1
    f(2)=2^2+f(1)=4+1=5
    f(3)=3^2+f(2)=9+5=14

    or you can write
    f(3)=3^2+f(2)=3^2+2^2+f(1)=3^2+2  ^2+1^1+f(0)=9+4+1+0=14
    Where does the 5 come from for 9+5?
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    (Original post by Maths94)
    Where does the 5 come from for 9+5?
    f(2)=5 one above
 
 
 
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