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# prove |sinx-siny|<=|x-y| watch

1. can anyone tell me how to do this. and x can't equal y

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2. (Original post by cooldudeman)
can anyone tell me how to do this. and x can't equal y

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One way is to use the mean value theorem.
3. (Original post by Hodor)
One way is to use the mean value theorem.
can you show it because I have no idea what that is

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4. (Original post by cooldudeman)
can you show it because I have no idea what that is

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It's something like:

"If f is differentiable on [x,y], then there is a c in [x,y] such that f(x) - f(y) = f'(c) (x-y)."

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Updated: November 19, 2013

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