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# Parallel Vectors M1 watch

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1. How do I do this?

I've got to (2+3lambda)i + (5-lamda)j
2. (Original post by zed963)
How do I do this?

I've got to (2+3lambda)i + (5-lamda)j
If that is parallel to i how much j will there be?
3. (Original post by TenOfThem)
If that is parallel to i how much j will there be?
Wouldn't they be the same?
4. (Original post by zed963)
How do I do this?

I've got to (2+3lambda)i + (5-lamda)j
If you imagine the vector i. Its horizontal to the x axis. So for a+λb to be parallel to i, the j component of your equation must equal 0, so a+λb is "parallel" to the x axis.
5. (Original post by zed963)
Wouldn't they be the same?
wouldn't what be the same
6. (Original post by TenOfThem)
wouldn't what be the same
The two vectors?
7. (Original post by zed963)
The two vectors?
Which 2 vectors?
8. (Original post by TenOfThem)
Which 2 vectors?
a and b.
9. I don't understand this properly, does anyone have something which explains it?
10. (Original post by zed963)
I don't understand this properly, does anyone have something which explains it?
If pi + qj is parallel to mi + nj

Then p = km and q= kn
11. (Original post by TenOfThem)
If pi + qj is parallel to mi + nj

Then p = km and q= kn
How have you got that?

if pi is parallel to mi then mi must be a factor of pi?
12. (Original post by zed963)
How have you got that?

if pi is parallel to mi then mi must be a factor of pi?
Yes but more than that

If mi + qj is parallel to ni

What do you know about q
13. (Original post by TenOfThem)
Yes but more than that

If mi + qj is parallel to ni

What do you know about q
q=0
14. (Original post by zed963)
q=0
Can you apply that to your original question
15. (Original post by TenOfThem)
Can you apply that to your original question
5-lamda=0?
16. (Original post by zed963)
5-lamda=0?
yes

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Updated: November 19, 2013
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