# Help with this question please!Watch

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#1
Acetic Acid (CH3COOH) is a weak acid. Ka= 1.8x 10-5

1. Write a chemical equation for the dissociation of acetic acid?

CH3COOH ---> CH3COO- + H+

2. Write the equilibrium (Ka) expression for the reaction?
Ka= [H+] [CH3COO-]
[CH3COOH]

3. Vinegar is a solution of 1.5 M acetic acid. What is the pH of vinegar at this concentration?
I'm not sure, any suggestions?

These are my answers, are they correct? I really appreciate the help, I'm having a tough time with this problem
0
5 years ago
#2
(Original post by EricRivers)
Acetic Acid (CH3COOH) is a weak acid. Ka= 1.8x 10-5

1. Write a chemical equation for the dissociation of acetic acid?

CH3COOH ---> CH3COO- + H+

2. Write the equilibrium (Ka) expression for the reaction?
Ka= [H+] [CH3COO-]
[CH3COOH]

3. Vinegar is a solution of 1.5 M acetic acid. What is the pH of vinegar at this concentration?
I'm not sure, any suggestions?

These are my answers, are they correct? I really appreciate the help, I'm having a tough time with this problem

check out this interactive on weak acids
0
#3
(Original post by charco)
check out this interactive on weak acids
wow that was very helpful, so would that make the pH for question 3 equal to a pH of 1.5? since it's a weak acid
0
5 years ago
#4
(Original post by EricRivers)
wow that was very helpful, so would that make the pH for question 3 equal to a pH of 1.5? since it's a weak acid
ka = [H+][A-]/[HA]

1.8 x 10-5 = [H+]2/1.5

[H+] = root(1.5 x 1.8 x 10-5)

[H+] = root(2.7 x 10-5)

[H+] = 0.0052

pH = 2.28
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