# Simplifying Arrhenius EquationWatch

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#1
help!!!,

I understand that you use logs but im unsure how you get from;

k = Ae^-Ea/RT to lnk=lnA-Ea/RT

THANKS GUYS!
0
#2
help!!!... I think Im getting rusty on logs (or i may not have the coorect understanding)

I understand that you use logs but im unsure how you get from;

k = Ae^-Ea/RT to lnk=lnA-Ea/RT

THANKS GUYS!
0
5 years ago
#3
(Original post by oranjuice)
help!!!,

I understand that you use logs but im unsure how you get from;

k = Ae^-Ea/RT to lnk=lnA-Ea/RT

THANKS GUYS!
You take logs to base e (natural logs)
0
5 years ago
#4
Like Charco said you take natural logs of both sides. So lnE^a/RT, the ln and e cancel so a/RT is left.
0
5 years ago
#5
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0
5 years ago
#6
(Original post by oranjuice)
help!!!... I think Im getting rusty on logs (or i may not have the coorect understanding)

I understand that you use logs but im unsure how you get from;

k = Ae^-Ea/RT to lnk=lnA-Ea/RT

THANKS GUYS!
Somehow I feel like I have seen this question earlier.

What will you get when you take a natural logarithm (base e) of both sides of the equation?
0
5 years ago
#7
(Original post by Borek)
Somehow I feel like I have seen this question earlier.

What will you get when you take a natural logarithm (base e) of both sides of the equation?
You are quite correct Borek...

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