Simplifying Arrhenius Equation Watch

oranjuice
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help!!!,

I understand that you use logs but im unsure how you get from;

k = Ae^-Ea/RT to lnk=lnA-Ea/RT

THANKS GUYS!
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oranjuice
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help!!!... I think Im getting rusty on logs (or i may not have the coorect understanding)

I understand that you use logs but im unsure how you get from;

k = Ae^-Ea/RT to lnk=lnA-Ea/RT

THANKS GUYS!
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charco
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(Original post by oranjuice)
help!!!,

I understand that you use logs but im unsure how you get from;

k = Ae^-Ea/RT to lnk=lnA-Ea/RT

THANKS GUYS!
You take logs to base e (natural logs)
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tsumannai
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Like Charco said you take natural logs of both sides. So lnE^a/RT, the ln and e cancel so a/RT is left.
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TSR Learn Together
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Borek
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(Original post by oranjuice)
help!!!... I think Im getting rusty on logs (or i may not have the coorect understanding)

I understand that you use logs but im unsure how you get from;

k = Ae^-Ea/RT to lnk=lnA-Ea/RT

THANKS GUYS!
Somehow I feel like I have seen this question earlier.

K = Ae^{-\frac{E_a}{RT}}

What will you get when you take a natural logarithm (base e) of both sides of the equation?
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charco
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(Original post by Borek)
Somehow I feel like I have seen this question earlier.

K = Ae^{-\frac{E_a}{RT}}

What will you get when you take a natural logarithm (base e) of both sides of the equation?
You are quite correct Borek...

... threads merged!
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