Probability Question

I think the question means the number generator gives random numbers that aren't necessarily whole numbers

Yep, I reread the question a second after I posted and realised my misunderstanding, my confusion still stands though. What happens when A=B?

Well what's the probabilty that A=B?

EDIT: Just realised the inclusive bit. But can someone explain to me the logic of P(A>B) = P(B>A) => P(A>B) = 1/2? The generator can still generate 2 of the same numbers?

Not sure if you get this now, but think about P(A<B) + P(A>B) = 1. Since P(A<B) and P(A>B) absorb all possibilities, we know the sum of these must = 1. Rearrange to get 1 - P(A<B) = P(A>B). We have P(A>B) = P(B>A), transforming the equation to 1 - P(A<B) = P(A<B), which becomes 1 = 2P(A<B) and from this you get the result!

Thanks for that, that makes sense. I'm right then that if the question said that only integers between 0 and 1 inclusive can be generated. Then P(A>B) = P(B>A) = 1/4 and P(A=B) = 1/2 ?