Ive balanced the equation to this which is 2NaN3→ 2Na + 3N2
A) How many grams of NaN3 are required to form 15.0g of N*2 gas?
How on earth do I work this out can someone show me the answer and working out as simply as possible
B) What volume would 15g of N2 gas produce at 170C and standard pressure?
Again confuses the hell outta me
A) work out the moles of N2 using the molarmass of N and 15g. Then just stochiometry to deduce the moles of NaN3 and from there just work out the grams needed using its molarmass.
For A: work out the mole ratio (3:2) wWork out the GFM of 2 moles of NaN3 and 3 moles of N2 GFM of 3N2 : GFM 2NaN3 1g 3N2 : GFM 2NaN3 divided by GFM of 3N2 15g : answer from above step. Hope this helped and made sense!
Ive balanced the equation to this which is 2NaN3→ 2Na + 3N2
A) How many grams of NaN3 are required to form 15.0g of N*2 gas?
How on earth do I work this out can someone show me the answer and working out as simply as possible
B) What volume would 15g of N2 gas produce at 170C and standard pressure?
Again confuses the hell outta me
A) Divide 15g by N2 molar mass to get moles of N2. As the ratio of N2 to NAN3 is 3:2, multiply the moles you just calculated by 2/3 to get the moles of NaN3. Now multiply these moles by NaN3 molar mass to get the grams of NaN3