# Easy differentiation question5t

#1

h(t)=-1/4t^2 +5e^-2t

h(t)=-5t^3-4t^2 / ln(5t)

Thanks!
0
8 years ago
#2
Instead of dy/dx you have dh/dt. Just differentiate like normal. Quotient rule for 2nd question.
0
#3
How? I don't know what e is or ln??
0
8 years ago
#4
If you don't know what e or ln are then you probably need to go back a few steps before attempting questions asking you to manipulate/differentiate them.
0
8 years ago
#5
(Original post by Dude Ranch)
How? I don't know what e is or ln??
You need to read back in your book or talk to your teacher - you need to know about exponential and logarithm functions before you can answer this question.
0
8 years ago
#6
(Original post by Dude Ranch)
How? I don't know what e is or ln??
We couldn't be expected to know this. See your teacher for help.
0
8 years ago
#7
Basically, if you raise e to any power, e^x, the gradient will be e to that power. y=lnx is the inverse function:

http://www.examsolutions.net/maths-r...tutorial-1.php

http://www.examsolutions.net/maths-r...tutorial-1.php

y=lnx => dy/dx=1/x

y=e^x => dy/dx=e^x

These videos should help:

http://www.examsolutions.net/maths-r...tutorial-1.php

http://www.examsolutions.net/maths-r...tutorial-1.php

You may also need to use the chain rule, as you have composite functions:

http://www.examsolutions.net/maths-r...tutorial-1.php

http://www.examsolutions.net/maths-r...tutorial-1.php
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