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Easy differentiation question5t
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Dude Ranch
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#1
Hi can you please help me differentiate these two questions and show me how, thanks:
h(t)=-1/4t^2 +5e^-2t
h(t)=-5t^3-4t^2 / ln(5t)
Thanks!
h(t)=-1/4t^2 +5e^-2t
h(t)=-5t^3-4t^2 / ln(5t)
Thanks!
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Nitrogen
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#2
Instead of dy/dx you have dh/dt. Just differentiate like normal. Quotient rule for 2nd question.
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Dude Ranch
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cambo211
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#4
If you don't know what e or ln are then you probably need to go back a few steps before attempting questions asking you to manipulate/differentiate them.
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davros
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(Original post by Dude Ranch)
How? I don't know what e is or ln??
How? I don't know what e is or ln??
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Mr M
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(Original post by Dude Ranch)
How? I don't know what e is or ln??
How? I don't know what e is or ln??
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Liamnut
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#7
Basically, if you raise e to any power, e^x, the gradient will be e to that power. y=lnx is the inverse function:
http://www.examsolutions.net/maths-r...tutorial-1.php
http://www.examsolutions.net/maths-r...tutorial-1.php
y=lnx => dy/dx=1/x
y=e^x => dy/dx=e^x
These videos should help:
http://www.examsolutions.net/maths-r...tutorial-1.php
http://www.examsolutions.net/maths-r...tutorial-1.php
You may also need to use the chain rule, as you have composite functions:
http://www.examsolutions.net/maths-r...tutorial-1.php
http://www.examsolutions.net/maths-r...tutorial-1.php
http://www.examsolutions.net/maths-r...tutorial-1.php
http://www.examsolutions.net/maths-r...tutorial-1.php
y=lnx => dy/dx=1/x
y=e^x => dy/dx=e^x
These videos should help:
http://www.examsolutions.net/maths-r...tutorial-1.php
http://www.examsolutions.net/maths-r...tutorial-1.php
You may also need to use the chain rule, as you have composite functions:
http://www.examsolutions.net/maths-r...tutorial-1.php
http://www.examsolutions.net/maths-r...tutorial-1.php
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