im struggling with a question here: given that 3xsin2x is a particular integral of the differentail equation d2y by dx^2 + 4y = kcos2x, where k is a constant, find the value of k
i found d2y by dx^2 to equal (1-12x)sin2x + 12cos2x
adding 4y gives 12cos2x + sin2x
therefore 12cos2x + sin2x = kcos2x
which is where im stuck, how do i find k, the constant?
im struggling with a question here: given that 3xsin2x is a particular integral of the differentail equation d2y by dx^2 + 4y = kcos2x, where k is a constant, find the value of k
i found d2y by dx^2 to equal (1-12x)sin2x + 12cos2x
adding 4y gives 12cos2x + sin2x
therefore 12cos2x + sin2x = kcos2x
which is where im stuck, how do i find k, the constant?