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Empirical formula

I think that this can't be done.

Compound c has a percentage composition by mass of 64.5% carbon, 9.1% for hydrogen and 36.4% oxygen. It's relative molecular mass is 88.

Calculate the empirical formula.

Isn't the compound percentage supposed to be 100% not 110%?






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Reply 1
Avatar for zed963
zed963
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ImageUploadedByStudent Room1386415302.839519.jpg

What I have done so far.


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If I was you, I'd use the values you're given.
Now divide by smallest amount in your case the value you for oxygen.
Do this for each and you should an answer.


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Reply 3
Avatar for zed963
zed963
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16
Original post by Girling1996
If I was you, I'd use the values you're given.
Now divide by smallest amount in your case the value you for oxygen.
Do this for each and you should an answer.


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I got C2H4O


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that looks right without doing any work.
Reply 5
Avatar for Borek
Borek
4
C2H4O contains not 64.5% of C, but 54.5. Chances are that's what was wrong with the data.

Original numbers don't yield anything reasonable, especially with molar mass around 88.
(edited 10 years ago)
Reply 6
Avatar for zed963
zed963
OP
16
Original post by Borek
C2H4O contains not 64.5% of C, but 54.5. Chances are that's what was wrong with the data.

Original numbers don't yield anything reasonable, especially with molar mass around 88.


Interesting I shall discuss this with my teacher.


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