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Optimisation Question

A rectangular box, with no top, is made from thin card.
The volume of the box is 500 cm3.
The base of the box is a square with sides of length x cm


(a)Show that the area, A cm2, of card used to make
such an open box is given by

A= x^2 + (2000/x)


(b) find the minimum amount of card needed to make this box


I have no idea how to do this.
Reply 1
Original post by 50ShadesOfRay
A rectangular box, with no top, is made from thin card.
The volume of the box is 500 cm3.
The base of the box is a square with sides of length x cm


(a)Show that the area, A cm2, of card used to make
such an open box is given by

A= x^2 + (2000/x)


(b) find the minimum amount of card needed to make this box


I have no idea how to do this.



Write down a formula using x and h (height) for volume
Set this = to the volume
Re-arrange to get h

Use this to write down an expression for the surface area
Reply 2
Original post by 50ShadesOfRay
A rectangular box, with no top, is made from thin card.
The volume of the box is 500 cm3.
The base of the box is a square with sides of length x cm


(a)Show that the area, A cm2, of card used to make
such an open box is given by

A= x^2 + (2000/x)


(b) find the minimum amount of card needed to make this box

I have no idea how to do this.


What part a or b or both or what? What did you do?
Reply 3
For the second part you want the lowest A. Think about differentiation and a minimum point:smile:
Reply 4
Original post by TenOfThem
Write down a formula using x and h (height) for volume
Set this = to the volume
Re-arrange to get h

Use this to write down an expression for the surface area



What about B, i can't work it out?
Reply 5
Original post by krisshP
For the second part you want the lowest A. Think about differentiation and a minimum point:smile:


Sorry i am confused, can you walk me threw it
Reply 6
You have an equation for A. Differentiate this equation to get dA/dx and set it equal to 0 and solve as the lowest A is at a turning point:smile:. Does that ring any bells for you?

Edit: think of a graph of A against x if it helps where the graph is a U shaped parabola, so it has a minimum point:smile:
(edited 10 years ago)
Reply 7
Original post by krisshP
You have an equation for A. Differentiate this equation to get dA/dx and set it equal to 0 and solve as the lowest A is at a turning point:smile:. Does that ring any bells for you?

Edit: think of a graph of A against x if it helps where the graph is a U shaped parabola, so it has a minimum point:smile:


Okay i understand that, however i am unsure how to set

-200x^-2 + 2x = 0

the answer is 600 by the way
(edited 10 years ago)
Reply 8
Original post by 50ShadesOfRay
Okay i understand that, however i am unsure how to set

-200x^-2 + 2x = 0



A= x^2 + (2000/x)
A=x^2 +2000x^-1
dA/dx=2x-2000x^-2
dA/dx=2x-2000/(x^2)
At minimum point dA/dx=0
2x-2000/(x^2)=0

Solve this, btw you messed up your differentiation a bit or did a typo error.

If you still struggle

Spoiler

Reply 9
Original post by krisshP
A= x^2 + (2000/x)
A=x^2 +2000x^-1
dA/dx=2x-2000x^-2
dA/dx=2x-2000/(x^2)
At minimum point dA/dx=0
2x-2000/(x^2)=0

Solve this, btw you messed up your differentiation a bit or did a typo error.

If you still struggle

Spoiler




that doesn't give 300 though
Reply 10
Original post by 50ShadesOfRay
that doesn't give 300 though


It gives x=10, right? Look at the question again. So you know worked out that the squared base of the box has sides of length 10cm. They wanted minimum amount of card needed, so you need A instead of x:smile:
Reply 11
Original post by krisshP
It gives x=10, right? Look at the question again. So you know worked out that the squared base of the box has sides of length 10cm. They wanted minimum amount of card needed, so you need A instead of x:smile:



You are the biggest legend! :biggrin:
Original post by TenOfThem
Write down a formula using x and h (height) for volume
Set this = to the volume
Re-arrange to get h

Use this to write down an expression for the surface area


ik this was 8 years ago but thanks, this exact question came up in my assignment

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