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is 4-methoxyphenol more or less acidic than phenol and why

What would the resonance be like in the protonated and deprotonated version of 4-methoxyphenol, and is it more or less acidic then phenol?
Reply 1
More acidic.
Original post by Kreme
More acidic.


Why? is it because once deprotonated the contribution the last resonance structure has means that it's more reactive and would want to get rid of at least one of the negative charges to decrease repulsion, and therefore want to hold onto its proton?

Reply 3
Original post by tammie123
Why? is it because once deprotonated the contribution the last resonance structure has means that it's more reactive and would want to get rid of at least one of the negative charges to decrease repulsion, and therefore want to hold onto its proton?


It explains here why phenol is more acidic.
http://chemwiki.ucdavis.edu/Organic_Chemistry/Organic_Chemistry_With_a_Biological_Emphasis/Chapter__7%3A_Organic_compounds_as_acids_and_bases/Section_7.4%3A_More_on_resonance_effects_on_acidity_and_basicity


Yeah I read that, but is my interpretation of it correct, or am I misunderstanding something?
The acidity of an acid is dependent on the stability of the conjugate base. The more resonance forms you can draw, the better. You've correctly determined that the negative charge is in no way benefiting from having the methoxy group in the para position, from a resonance point of view. However, it would be better to draw how the negative charge is delocalised into the ring (rather than the electrons in the methoxygroup) - this shows the same pattern as plain old phenol. Then you could add a bit about the methoxy group being electron donating as you've done above.
(edited 10 years ago)
Original post by EierVonSatan
The acidity of an acid is dependent on the stability of the conjugate base. The more resonance forms you can draw, the better. You've correctly determined that the negative charge is in no way benefiting from having the methoxy group in the para position, from a resonance point of view. However, it would be better to draw how the negative charge is delocalised into the ring (rather than the electrons in the methoxygroup) - this shows the same pattern as plain old phenol. Then you could add a bit about the methoxy group being electron donating as you've done above.


Thank you so much! :smile:

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