a little calculus... Watch

Chewwy
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#1
Report Thread starter 12 years ago
#1
b'(t) = -cr(t)
r'(t) = -kb(t)

...c and k positive constants. show that:

d(kb(t)^2-cr(t)^2)/dt = 0
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steve10
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#2
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d(kb² - cr²) / dt =
2kb.b' - 2cr.c' =
2kb(-cr) - 2cr(-kb) =
-2kbcr + 2kbcr =
0
==
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Chewwy
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#3
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#3
****.
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