scorpio22
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#1
Report Thread starter 7 years ago
#1
A container of very small mass has 0.02 kg of ice and 0.1 kg of
water. Steam at 100 oC is passed through the container until all
the ice has just melted. How much water is there in the
container now?

latent heat of vaporisation for steam = 2.3 x 106
Jkg-1
latent heat of fusion for ice = 3.4 x 105
Jkg-1
specific heat capacity of water = 4.2 x 103
Jkg-1K
-1

Qice= mxlf
= 0.02 x 3.4 x 10^5=6800

Qwater=m x c x temp
=0.1 x 4.2x10^3=


i am a bit stuck of my next step.any ideas.thank you
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scorpio22
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#2
Report Thread starter 7 years ago
#2
A container of very small mass has 0.02 kg of ice and 0.1 kg of
water. Steam at 100 oC is passed through the container until all
the ice has just melted. How much water is there in the
container now?

latent heat of vaporisation for steam = 2.3 x 106
Jkg-1
latent heat of fusion for ice = 3.4 x 105
Jkg-1
specific heat capacity of water = 4.2 x 103
Jkg-1K
-1

Qice= mxlf
= 0.02 x 3.4 x 10^5=6800

Qwater=m x c x temp
=0.1 x 4.2x10^3=


i am a bit stuck of my next step.any ideas.thank you
0
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Borek
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#3
Report 7 years ago
#3
You can easily calculate amount of heat required to melt the ice. Now, think where does the heat to melt the ice come from. Hint: what happens to steam?
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