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# Rearranging formula question help watch

1. I need help solving this equation
P = 5xy + y
I have tried to approach this by dividing each side by y so we end up with
P/y = 5x
Its obvious right now that I have divide by 5
Is the answer x = P/5y? Or is it x= (P/y)/5?
2. (Original post by socialgain)
I need help solving this equation
P = 5xy + y
I have tried to approach this by dividing each side by y so we end up with
P/y = 5x
Its obvious right now that I have divide by 5
Is the answer x = P/5y? Or is it x= (P/y)/5?
The bold line is wrong. What happened to the + y ?

Which variable are you trying to make the subject?
3. (Original post by socialgain)
I need help solving this equation
P = 5xy + y
I have tried to approach this by dividing each side by y so we end up with
P/y = 5x
Its obvious right now that I have divide by 5
Is the answer x = P/5y? Or is it x= (P/y)/5?
Factorising 5xy+y gives y(5x+1).
4. (Original post by notnek)
The bold line is wrong. What happened to the + y ?

Which variable are you trying to make the subject?
Whoops its meant to be
P = 5xy + y
Make x the subject
P - y = 5xy
(P - y)/y = 5x
Where should I go from here?
5. (Original post by majmuh24)
Factorising 5xy+y gives y(5x+1).
Sorry I should of specified that I am trying to make X the subject
6. (Original post by socialgain)
Sorry I should of specified that I am trying to make X the subject
I know, and you can do that by factorising. Instead of 5xy+y, rearrange P=y(5x+1) to get x (it should be a lot easier)
7. P = 5xy + y
= y(5x + 1)
P/y = 5x + 1
5x = P/y - 1
x = (
P/y - 1)/5
8. (Original post by socialgain)
Whoops its meant to be
P = 5xy + y
Make x the subject
P - y = 5xy
(P - y)/y = 5x
Where should I go from here?
When you divided by y you should have divided by 5y
9. (Original post by TenOfThem)
When you divided by y you should have divided by 5y
So would the final answer be
P = 5xy + y
P-y = 5xy
(P-y)/5y = X
X = (p-y)/5y
Thanks for the help also could I pm you for help on one more question?
10. (Original post by socialgain)
So would the final answer be
P = 5xy + y
P-y = 5xy
(P-y)/5y = X
X = (p-y)/5y
Yes

Thanks for the help also could I pm you for help on one more question?
11. (Original post by TenOfThem)
Yes

Could you check if this is right?
W = 2y/3 (1+P)
3W=2y(1+p)
3w=2y+2yp
3w/2y=2+p
3w/2y - 2 = p
12. W = 2y/3 (1+P)
3W=2y(1+p)
3W/2y=(1+P)
P = 3W/2y - 1
13. (Original post by socialgain)
Could you check if this is right?
W = 2y/3 (1+P)
3W=2y(1+p)
3w=2y+2yp
3w/2y=2+p
3w/2y - 2 = p
Assuming this is

2y/2y is 1 not 2

Though to be honest you should just have divided by 2y at this point
14. (Original post by TenOfThem)
Assuming this is

2y/2y is 1 not 2

Though to be honest you should just have divided by 2y at this point
3W = 2y(1+p)
3W/2y = (1+p)
3W/2y = 1+p
3w/2y - 1 = p

Is that right?
15. (Original post by socialgain)
3W = 2y(1+p)
3W/2y = (1+p)
3W/2y = 1+p
3w/2y - 1 = p

Is that right?
yes
16. (Original post by TenOfThem)
yes
Thanks for all the help I appreciate it!
17. (Original post by mc1996)
W = 2y/3 (1+P)
3W=2y(1+p)
3W/2y=(1+P)
P = 3W/2y - 1
Thanks for all the help I appreciate it!
18. (Original post by socialgain)
Thanks for all the help I appreciate it!
No Problem
19. (Original post by mc1996)
No Problem
T = Square root 2s/g
Make g the subject
Could you should me the method in solving this? thanks
20. (Original post by socialgain)
T = Square root 2s/g
Make g the subject
Could you should me the method in solving this? thanks
T = Square root 2s/g
T2 = 2s/g
g T2=2s
2s/T2 = g

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