I have attached the question in the post. Here is what I have done so far.
Let![]()
And I got the auxiliary equation of![]()
Therefore
So the complimentary function is
So the overall general solution would be
I just don't know how to get the particular integral and particular solution. Help please?
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CharlieBoardman
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- 21-01-2014 13:39
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Robbie242
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- 21-01-2014 13:44
(Original post by CharlieBoardman)
I have attached the question in the post. Here is what I have done so far.
Let
And I got the auxiliary equation of
Therefore
So the complimentary function is
So the overall general solution would be
I just don't know how to get the particular integral and particular solution. Help please?(1) (since our differential equation is equal to 6x-5) where
are constants. Also your C.F is just
work separately and then combine the particular integral and complimentary function to gain a general solution
Differentiate this expression (1) once, and then again to then be plugged back into our initial differential equation to find out the values ofand
Last edited by Robbie242; 21-01-2014 at 13:47. -
natninja
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- 21-01-2014 13:45
(Original post by CharlieBoardman)
I have attached the question in the post. Here is what I have done so far.
Let
And I got the auxiliary equation of
Therefore
So the complimentary function is
So the overall general solution would be
I just don't know how to get the particular integral and particular solution. Help please?
Then to find your particular solution you should simply apply the boundary conditions to your solution and d/dx of your solution. -
brianeverit
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- 23-01-2014 11:56
(Original post by CharlieBoardman)
I have attached the question in the post. Here is what I have done so far.
Let
And I got the auxiliary equation of
Therefore
So the complimentary function is
So the overall general solution would be
I just don't know how to get the particular integral and particular solution. Help please?
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