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# hi watch

1. solve 2^x+2y=1 nd 3^2x+y=27 simultaenously pls thnks
2. (Original post by tariqballe)
solve 2^x+2y=1 nd 3^2x+y=27 simultaenously pls thnks
substitute that into to solve for x and then plug back in for y
3. (Original post by Robbie242)
substitute that into to solve for x and then plug back in for y
Actuall ythrough elimination
4. (Original post by tariqballe)
Actuall ythrough elimination

What on earth does this mean
5. (Original post by tariqballe)
Actuall ythrough elimination
I assume you want it using the other method? It's much easier to substitute in cases like this because otherwise you'd end up taking away numbers with different powers (which is a lot harder to solve).
6. (Original post by k4l397)
I assume you want it using the other method? It's much easier to substitute in cases like this because otherwise you'd end up taking away numbers with different powers (which is a lot harder to solve).
Its actually 2^x+2y=2^0 so itz easier eliminating
7. (Original post by tariqballe)
Its actually 2^x+2y=2^0 so itz easier eliminating
nonsense

please explain what your issue is - if you feel that you can answer the question using a different one to the one suggested then your question is answered - but the suggestion made by Robbie is the sensible approach
8. (Original post by tariqballe)
solve 2^x+2y=1 nd 3^2x+y=27 simultaenously pls thnks
Are you trying to solve the equations suggested by Robbie, or are you actually trying to solve the equations and , which are much simpler to solve?
9. (Original post by davros)
Are you trying to solve the equations suggested by Robbie, or are you actually trying to solve the equations and , which are much simpler to solve?
By Jove, I think he's cracked it!
10. (Original post by Mr M)
By Jove, I think he's cracked it!
Robbie's equations were too hard so I changed the problem into one I could solve more easily

Ready for some 'Tough Young Teachers' tonight?
11. (Original post by davros)
Ready for some 'Tough Young Teachers' tonight?
I prefer reality TV so I've chosen Benidorm.
12. (Original post by davros)
Are you trying to solve the equations suggested by Robbie, or are you actually trying to solve the equations and , which are much simpler to solve?
prsom
13. (Original post by TenOfThem)
nonsense

please explain what your issue is - if you feel that you can answer the question using a different one to the one suggested then your question is answered - but the suggestion made by Robbie is the sensible approach
2^x+2y=2^0
x+2y=0----i
then 3^2x+y=3^3
so 2x+y=3----ii
so x+2y=0--*2
2x+y=3 --*1

therefore 2x+4y=0---ii
-
2x+y=3
0+3y=-3
so y=-1 then plug it bck into any equations to find x
14. (Original post by tariqballe)
2^x+2y=2^0
x+2y=0----i
then 3^2x+y=3^3
so 2x+y=3----ii
so x+2y=0--*2
2x+y=3 --*1

therefore 2x+4y=0---ii
-
2x+y=3
0+3y=-3
so y=-1 then plug it bck into any equations to find x
So, now you have shown that you were asking a completely different question to the one that you posted

You can do the question so there is no issue

And, either elimination or substitution are very straightforward with the equations that you had

If you want continued help, I suggest that in future
• Post the correct question
• Thank people for their help or suggestions
• Let people know when you have solved the problem
15. (Original post by tariqballe)
2^(x+2y)=2^0
x+2y=0----i
Those are brackets.
16. (Original post by BabyMaths)
Those are brackets.
lol.........
17. Is this FP1???

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18. (Original post by benwalters1996)
Is this FP1???

Posted from TSR Mobile
Looks more like GCSE to be honest
19. (Original post by davros)
Looks more like GCSE to be honest
Why leave it so late?
20. At least the word 'solve' is correct in the opening post. That's something.

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