# How Was P2

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16 years ago
#21
for the other integration question i got 9-8ln2 i think or sumthin like that
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16 years ago
#22
i got pi(9ln2 + 8)

im quite sure about it, i approximated the area to the difference of two cones i got 49.325425 something something.

pi(9ln2 + 8) = 44.7

so i gess that close enuff
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16 years ago
#23
can anyone care to explain how they got it!! ( finding the area of R for question 7 )
pls!
thnks
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16 years ago
#24
yeah i got 9-8ln2 !!!!
woohoo,, at least i know i got one right,,, all my methods are right, i just screwed up the accuracy marks.
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16 years ago
#25
(x - 1)^2 + 2 = 2 when x = 1 not -1!!!!
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16 years ago
#26
pretty sure it was 8ln2 because i got it from 4ln4
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16 years ago
#27
50/100 would be a resdpectable mark for this paper
i messed up on the graphs and volumes and identits
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16 years ago
#28
fot the area, u integate the curve between o and ln4, , then add the area of the trianlge which is 14-ln4/2 x 13, then add together to get, 97-3ln2
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16 years ago
#29
Was there a mistake in Q8 i)? instead of a 3 there should have been a factor of two? I think.
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16 years ago
#30
there was no mistake in any of the questions and it was piss easy. i guess this proves the theory that AS papers are easy this year and A2 are a *****. S1, P1 and P2 all easy.
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16 years ago
#31
This question is the same as Q18 on Page 71 (Exercise 4C) of the Heinmann A-level Pure Mathematics 2 book, except 1 over everything.
(1-cos2x)/sin2x = tanx

It is in fact identical to Q6)a) in the January 2002 Pure Mathematics 2 paper.

Prove by contradiction that Edexcel do recycle past questions.
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16 years ago
#32
Well if edexcel want to give us free marks who are we to complain?
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16 years ago
#33
edexcel tha best innit u cheater (aj)
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16 years ago
#34
Did anyone else get the last part of Q8 to give tanx = 1/2

hence the solutions being something like 25.57 degrees, and (180 + 25.57)???

or was it something completely different?

plus how do u prove c = 4p^2?
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16 years ago
#35
i got that, tan x=1/2
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16 years ago
#36
u had to do dy/dx of the function and put it equal to the given gradient of -4
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16 years ago
#37
For question 1 b... did you guys get x =1/5 ???
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16 years ago
#38
yep, and so did evry1 else i talked 2.
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16 years ago
#39
no i got x=3?? anyone get that?
what did ppl get for A and p??? on question 4or5 cant remember which
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16 years ago
#40
What did the graphs for part (a), (b) and part (c) of the functions question look like?

(a) y= f(x+1)
(b) y= |f(x)|
(c) y= f(|x|)

Was part (a) identical in shape to f(x) except moved 1 places to the left, in the negative x direction? Therefore changing x-axis crossing point, turning points.

Was part (b) that it did not go into the negative y-axis and so bounced back off the x-axis?

and part (c), where x goes negative is a reflection of the y-axis as far as x=-1?
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