C4 help please
Q8
I integrated: sec(x)-2 to get pi[(tan(x)-4x)] I subbed in pi/3 and -pi/3
And got pi(2sqrt3 - 4pi/3)
I integrated: sec(x)-2 to get pi[(tan(x)-4x)] I subbed in pi/3 and -pi/3
And got pi(2sqrt3 - 4pi/3)
Original post by Vorsah
Q8
I integrated: sec(x)-2 to get pi[(tan(x)-4x)] I subbed in pi/3 and -pi/3
And got pi(2sqrt3 - 4pi/3)
I integrated: sec(x)-2 to get pi[(tan(x)-4x)] I subbed in pi/3 and -pi/3
And got pi(2sqrt3 - 4pi/3)
The integral of Sec(x) is not Tan(x)
Original post by Vorsah
The answer is:
8pi^(2/3) - 2pi(sqrt3)
8pi^(2/3) - 2pi(sqrt3)
Just looked at the question and realised that you were actually integrating
You need to do 2 - secx
(edited 10 years ago)
Original post by TenOfThem
Just looked at the question and realised that you were actually integrating
Yh I integrated sec^2x-4 to get (tanx-4x)pi
Why do I need to do 2-secx and not secx-2?
(edited 10 years ago)
Original post by Vorsah
Yh I integrated sec^2x-4 to get (tanx-4x)pi
Why do I need to do 2-secx and not secx-2?
Why do I need to do 2-secx and not secx-2?
Because you need big volume - small volume
Original post by TenOfThem
Because you need big volume - small volume
Okay
Say if the question was: find the volume of the solid formed when the curve y=secx is rotated through 2pi radians between -pi/3 and pi/3
Would you just integrated sec^2x to get tanx then go from there?
You want to find the shaded region rotated through 2pi radians
Original post by Vorsah
Okay
Say if the question was: find the volume of the solid formed when the curve y=secx is rotated through 2pi radians between -pi/3 and pi/3
Would you just integrated sec^2x to get tanx then go from there?
Say if the question was: find the volume of the solid formed when the curve y=secx is rotated through 2pi radians between -pi/3 and pi/3
Would you just integrated sec^2x to get tanx then go from there?
yes
Original post by TenOfThem
yes
I got (8pi^2)/3 -2pi(sqrt3)
The answer in the book is (8pi^(2/3))/3 -2pi(sqrt3), is this a mistake?
Original post by Vorsah
I got (8pi^2)/3 -2pi(sqrt3)
The answer in the book is (8pi^(2/3))/3 -2pi(sqrt3), is this a mistake?
The answer in the book is (8pi^(2/3))/3 -2pi(sqrt3), is this a mistake?
I agree with you
Original post by TenOfThem
I agree with you
Thanks for your help
Original post by TenOfThem
Because you need big volume - small volume
Ten of them how old are you
Posted from TSR Mobile
Original post by The_Blade
51, how old are you
Original post by TenOfThem
51, how old are you
he is too young for you
Original post by the bear
he is too young for you
They all are
Original post by TenOfThem
They all are
i think Davros is quite erm mature
Original post by the bear
i think Davros is quite erm mature
Maybe
I thought Mr M was my best bet
Original post by TenOfThem
Maybe
I thought Mr M was my best bet
I thought Mr M was my best bet
there have been rumours....
Original post by the bear
there have been rumours....
I know, I started them
Original post by TenOfThem
I know, I started them
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