ViciousPenguin
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#1
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Hi I have a question I just can't get my head around, hopefully someone could help me out!

1. Express as a single logarithm-

log(x+1)-log(x-6)+2logx
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Prince Philip
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(Original post by ViciousPenguin)
Hi I have a question I just can't get my head around, hopefully someone could help me out!

1. Express as a single logarithm-

log(x+1)-log(x-6)+2logx
What have you tried? Do you know how to combine sums of logs?

This will help: 2\log x = \log x^2
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shawn_o1
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log(ab) = log(a) + log(b)
log(a/b) = log(a) - log(b)
log(a^k) = k log(a)

Isn't that in the C2 text book if you have one?
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Chlorophile
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(Original post by ViciousPenguin)
Hi I have a question I just can't get my head around, hopefully someone could help me out!

1. Express as a single logarithm-

log(x+1)-log(x-6)+2logx
Remember that log(a)+log(b)=log(a*b) and log(a)-log(b)=log(a/b)
Also remember that xlog(a)=log(ax)

That's all you need for this question.
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TenOfThem
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(Original post by ViciousPenguin)
Hi I have a question I just can't get my head around, hopefully someone could help me out!

1. Express as a single logarithm-

log(x+1)-log(x-6)+2logx
\log (a) + \log (b) = \log (ab)

\log (a) - \log (b) = \log (\frac{a}{b})

m\log (a) = \log (a^m)
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