Jargonium
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#1
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#1
I got a question that asks what is formed in the initiation step in the mechanism of the chlorination of methane.

Before I looked at the possible answers I knew it was chlorine radicals.

Then when I went to circle that it wasn't there..

The possible answers are:


  • hydrogen atoms
  • hydrogen chloride
  • methyl radicals
  • chlorine atoms

Am I correct in thinking this was a typo or am I wrong entirely?

Assistance greatly appreciated!
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EierVonSatan
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The right answer is amongst the choices :yep:

What is a chlorine radical's electronic configuration?
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Jargonium
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(Original post by EierVonSatan)
The right answer is amongst the choices :yep:

What is a chlorine radical's electronic configuration?
A radical is a particle with a single unpaired electron.

Therefore, whenever I write the initiation step I show that under UV light, Cl2 turns to 2Cl radicals as one electron jumps from the covalent bond to each chlorine (which is homolytic fisson).

That means that the electronic configuration would be:

[Ne] 3s2 3p4

I still think the answer is chlorine radicals!

Sorry, please explain
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EierVonSatan
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(Original post by Jargonium)
A radical is a particle with a single unpaired electron.

[Ne] 3s2 3p4
No..

Cl2 is a neutral molecule (34 protons, 34 electrons) and is split into two by UV light:

Cl2 ---> 2Cl

Leaving two neutral Cl's (17 protons, 17 electrons) with configuration [Ne] 3s2 3p5

I still think the answer is chlorine radicals!
You're correct. Does this help??
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Borek
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(Original post by Jargonium)
[Ne] 3s2 3p4
Try to assign charge to this configuration.

And note it doesn't have any unpaired electrons.
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Jargonium
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(Original post by EierVonSatan)
No..

Cl2 is a neutral molecule (34 protons, 34 electrons) and is split into two by UV light:

Cl2 ---> 2Cl

Leaving two neutral Cl's (17 protons, 17 electrons) with configuration [Ne] 3s2 3p5



You're correct. Does this help??
Oh my goodness, thank you, I get you now!

Thanks!!
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