This is because the ethanoate ions will interact with the water to remove the hydrogen ions (H+). The ethanoic acid formed in the equilbrium is a very weak acid and hence only partially dissociates, pulling the equilibrium to the RIGHT HAND SIDE of the equation.
CH3COO- + H2O <==> CH3COOH + OH-
Therefore, the sodium ethanoate is said to be akaline by hydrolysis (the chemical breakdown of a compound due to reaction with water).
CH3COO- + H2O <==> CH3COOH + OH-
Therefore, the sodium ethanoate is said to be akaline by hydrolysis (the chemical breakdown of a compound due to reaction with water).
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