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[REGARDING EDEXCEL MECHANICS 1 JAN 2010 and JAN 2011]
In the Jan paper question 4c
Jan 2010 question 4c
it tells us that the moments at C is 8x the moments at A.
SO the mark scheme tells us C = 8A
HOWEVER
In the June paper question 4,
June 2010 question 4
it tells us the moments in D is 3x the moments at C.
BUT the mark scheme says 3D = C
so im really confused which ones correct... shouldn't the Jan 2010 paper say 8C = A???
could someone explain whether im right, or Edexcel is right and WHY?
thanks
In the Jan paper question 4c
Jan 2010 question 4c
it tells us that the moments at C is 8x the moments at A.
SO the mark scheme tells us C = 8A
HOWEVER
In the June paper question 4,
June 2010 question 4
it tells us the moments in D is 3x the moments at C.
BUT the mark scheme says 3D = C
so im really confused which ones correct... shouldn't the Jan 2010 paper say 8C = A???
could someone explain whether im right, or Edexcel is right and WHY?
thanks
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(Original post by queenfatso)
[REGARDING EDEXCEL MECHANICS 1 JAN 2010 and JAN 2011]
In the Jan paper question 4c
Jan 2010 question 4c
it tells us that themoments (reaction force!) at C is 8x the moments (reaction force!) at A.
SO the mark scheme tells us C = 8A
HOWEVER
In the June paper question 4,
June 2010 question 4
it tells us themoments (reaction force) in D is 3x the moments (reaction force) at C.
BUT the mark scheme says 3D = C
so im really confused which ones correct... shouldn't the Jan 2010 paper say 8C = A???
could someone explain whether im right, or Edexcel is right and WHY?
thanks
[REGARDING EDEXCEL MECHANICS 1 JAN 2010 and JAN 2011]
In the Jan paper question 4c
Jan 2010 question 4c
it tells us that the
SO the mark scheme tells us C = 8A
HOWEVER
In the June paper question 4,
June 2010 question 4
it tells us the
BUT the mark scheme says 3D = C
so im really confused which ones correct... shouldn't the Jan 2010 paper say 8C = A???
could someone explain whether im right, or Edexcel is right and WHY?
thanks
I see no problem at all with the workings of the two papers...
First off they haven't quantified the "moment" but the "reaction force" at the points.
I don't see how the mark scheme for the June paper implies that! Look at the pic
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(Original post by RoyalBlue7)
I don't see how the mark scheme for the June paper implies that! Look at the pic
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I don't see how the mark scheme for the June paper implies that! Look at the pic
but is the reaction force for the June paper 3D = C?
it isnt consistent with the Jan paper..
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#4
(Original post by queenfatso)
but is the reaction force for the June paper 3D = C?
it isnt consistent with the Jan paper..
but is the reaction force for the June paper 3D = C?
it isnt consistent with the Jan paper..
The question reads:
4. A beam AB has length 6 m and weight 200 N. The beam rests in a
horizontal position on two supports at the points C and D, where AC =1 m and DB =1 m. Two children, Sophie and Tom, each of weight 500 N, stand on the beam with Sophie standing twice as far from the end B as Tom. The beam remains horizontal and in equilibrium and the magnitude of the reaction at D is three times the magnitude of the reaction at C. By modelling the beam as a uniform rod and the two children as particles, find how far Tom is standing from the end B.
end B.
So D=3C
The Jan paper question mentions:
Given that the tension in the rope attached to the pole at C is eight times the tension in the rope attached to the pole at A...
(It's not reaction force here, my bad)
So C=8A
If you do not know where to put the number just substitute a value and inspect...
it tells us the moments in D is 3x the moments at C.
BUT the mark scheme says 3D = C
BUT the mark scheme says 3D = C
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hmmm...
im still really confused about the wording of how Edexcel phrased the question
if C is 3 times then shouldn't C be 3C? Because it's 8x greater than D...
im still really confused about the wording of how Edexcel phrased the question
if C is 3 times then shouldn't C be 3C? Because it's 8x greater than D...
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