queenfatso
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[REGARDING EDEXCEL MECHANICS 1 JAN 2010 and JAN 2011]


In the Jan paper question 4c
Jan 2010 question 4c

it tells us that the moments at C is 8x the moments at A.
SO the mark scheme tells us C = 8A


HOWEVER
In the June paper question 4,
June 2010 question 4

it tells us the moments in D is 3x the moments at C.
BUT the mark scheme says 3D = C



so im really confused which ones correct... shouldn't the Jan 2010 paper say 8C = A???



could someone explain whether im right, or Edexcel is right and WHY?

thanks
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RoyalBlue7
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(Original post by queenfatso)
[REGARDING EDEXCEL MECHANICS 1 JAN 2010 and JAN 2011]


In the Jan paper question 4c
Jan 2010 question 4c

it tells us that the moments (reaction force!) at C is 8x the moments (reaction force!) at A.
SO the mark scheme tells us C = 8A


HOWEVER
In the June paper question 4,
June 2010 question 4

it tells us the moments (reaction force) in D is 3x the moments (reaction force) at C.
BUT the mark scheme says 3D = C



so im really confused which ones correct... shouldn't the Jan 2010 paper say 8C = A???



could someone explain whether im right, or Edexcel is right and WHY?

thanks
Both the papers linked are the same; you've linked both to the January paper!

I see no problem at all with the workings of the two papers...

First off they haven't quantified the "moment" but the "reaction force" at the points.

I don't see how the mark scheme for the June paper implies that! Look at the pic


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queenfatso
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(Original post by RoyalBlue7)

I don't see how the mark scheme for the June paper implies that! Look at the pic


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but is the reaction force for the June paper 3D = C?

it isnt consistent with the Jan paper..
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RoyalBlue7
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(Original post by queenfatso)
but is the reaction force for the June paper 3D = C?

it isnt consistent with the Jan paper..
It's a May paper, isn't it?

The question reads:

4. A beam AB has length 6 m and weight 200 N. The beam rests in a
horizontal position on two supports at the points C and D, where AC =1 m and DB =1 m. Two children, Sophie and Tom, each of weight 500 N, stand on the beam with Sophie standing twice as far from the end B as Tom. The beam remains horizontal and in equilibrium and the magnitude of the reaction at D is three times the magnitude of the reaction at C. By modelling the beam as a uniform rod and the two children as particles, find how far Tom is standing from the end B.
end B.

So D=3C

The Jan paper question mentions:

Given that the tension in the rope attached to the pole at C is eight times the tension in the rope attached to the pole at A...

(It's not reaction force here, my bad)

So C=8A

If you do not know where to put the number just substitute a value and inspect...

it tells us the moments in D is 3x the moments at C.
BUT the mark scheme says 3D = C
No :confused:
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queenfatso
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hmmm...

im still really confused about the wording of how Edexcel phrased the question



if C is 3 times then shouldn't C be 3C? Because it's 8x greater than D...
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queenfatso
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EXAM SOLUTIONS VIDEO

have a look at the exam solution video's diagram... they state its ​3D...
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