Merdan
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Report Thread starter 7 years ago
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In triangle AOB, AM : MB = 2:1 where M lies on the line AB. If OA = a , and OB = b find OM in terms of a and b. I got OM = a/3 + 2b/3. The answer is a/3 - 2b/3. I tried using different direction notations. I got a/3 + 2b/3 all the time if someone manages to get a/3 - 2b/3 can you show how you did please lol.
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user2020user
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Report 7 years ago
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(Original post by Merdan)
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You're right!

\vec{OM} = \dfrac{\vec{a}}{3}  + \dfrac{2\vec{b}}{3}
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