[SOLVED] C3 - The Exponential Function and Natural Logarithm Theory

Hey guys, back again.

Not an exam question this time, just a bit of theory I either missed or have completely forgotten...

When working with the Exponential Function and Natural Logarithms I understand the basics, such as:

e^[Ln(4)] = 4

Reading over my textbook I have seen this however and it has totally baffled me, and I don't quite understand how I would show it.

e^[ln(x)-1] = x/e
e^[ln(x)-2] = x/e^(2)
e^[ln(x)-2] = x/e^(3)
and so on...

Could someone show me why this is the case?
Thanks,

I'll do the first one for you

$e^{\ln(x)-1}=e^{\ln(x)}*e^{-1}$ (when you multiply you add the powers)

$e^{\ln(x)-1}=xe^{-1}$ and $e^{-1}=\dfrac{1}{e}$ so $e^{\ln(x)-1}=\dfrac{x}{e}$