Differential Question Help

The question states: "Fluid flows out of a cylindrical tank with a constant cross section. At time t, the volume of fluid remaining in the tank in V. The rate at which the fluid flows is proportional to the square root of V. Show that the depth h of the fluid in the tank satisfies the differential equation dh/dt = -k√h, where k is a positive constant"

What I did so far: dh/dt ∝-√V
so dh/dt=-k√V
What do I do now guys, you help is greatly appreciated! =)

Your first line should be $\frac{dV}{dt}$ is proportional to $\sqrt{V}$


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Why is it dV/dt that opposed to dh/dt? =)