The Student Room Group

Help with a general maths question, please

Scroll to see replies

Original post by yellsah2
Good to see someone having a bit of fun with something that stretches the mind ,
a lot of gobbledygook answers, and they were fun....to look at...

But one person said, Answer is 12 , correct ...

But how do we get 12 is the real knowledge,

ie, someone my have the right theory, and get the wrong answer,
no problem, as its the theory first, then maths.

Wanna know how 12 ? Have a good Sunday.



Thanks!

I figured out how to get 12. Basically, we know that (a+b) = 3 and (c+w) = 4. If we expand the brackets on (a+b) and (c+w), we get ac+aw+bc+bw = 12 and there we have it! Our answer!

Thanks for the reply!
Reply 21
Original post by Indeterminate
Factorise everything

Hint:

ab+bc=c(a+b)ab+bc = c(a+b)


Just for anyone who was confused by this, this isnt actually quite right. I think he meant:

ab+bc=b(a+c)ab+bc = b(a+c)
Reply 22
Original post by londoncricket
Thanks!

I figured out how to get 12. Basically, we know that (a+b) = 3 and (c+w) = 4. If we expand the brackets on (a+b) and (c+w), we get ac+aw+bc+bw = 12 and there we have it! Our answer!

Thanks for the reply!


Whoo there,
Lets first take (c+w)

Tell me what is the value of, C = _ ?
& the value of, W= _ ?

and how,
do we know they are these values ?
Reply 23
Original post by yellsah2
Whoo there,
Lets first take (c+w)

Tell me what is the value of, C = _ ?
& the value of, W= _ ?

and how,
do we know they are these values ?


How much have you had to drink, mate?
Reply 24
Original post by newblood
How much have you had to drink, mate?


pint and a half, with algerbretic chasers !

Quick Reply

Latest