qwerty321321
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Why does -log49-log36 = -3.45
but -log(49/36) = -0.134
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TenOfThem
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(Original post by qwerty321321)
Why does -log49-log36 = -3.45
but -log(49/36) = -0.134
Why wouldn't they

Did you think that -\log 49 -\log 36 = -\log (\frac{49}{36})?
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qwerty321321
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so how would you work out
-log49-log36
to find the answer as a log
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WishingChaff
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You have made a minor error with your minus signs. If I was to write your equation as follows it should hopefully shed some light"

-log(49) - log(36) = -(log(49) + log(36))

Using rues of logs, what does that equal?

(Original post by qwerty321321)
Why does -log49-log36 = -3.45
but -log(49/36) = -0.134
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TenOfThem
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(Original post by qwerty321321)
so how would you work out
-log49-log36
to find the answer as a log
-\log 49 -\log 36 = -[\log 49 + \log 36]

Does that help
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