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C3 differentiation

Hi,

I got the right answer with this question, but only by messing around with it and not really understanding the logic behind what I was doing. Could anyone explain why what I did gave the correct answer..it really doesn't make sense to me.

The radius, r cm, of a circular ink spot, t seconds, after it first appears, is given by:

r=1+4t2+t \frac{1+4t}{2+t} The initial size is found by letting t=0.

Calculate the time taken for the radius to double its initial size.

So, initially I thought to double the RHS as the radius has doubled. But that was wrong. Then, just messing a little, I let r=1 and then found t. t=1/3, which is correct. But how so? There is nothing to indicate that r was 0.5. I'm not sure of the logic....could anyone explain? Thanks!
Reply 1
Original post by marcsaccount
Hi,

I got the right answer with this question, but only by messing around with it and not really understanding the logic behind what I was doing. Could anyone explain why what I did gave the correct answer..it really doesn't make sense to me.

The radius, r cm, of a circular ink spot, t seconds, after it first appears, is given by:

r=1+4t2+t \frac{1+4t}{2+t} The initial size is found by letting t=0.

Calculate the time taken for the radius to double its initial size.

So, initially I thought to double the RHS as the radius has doubled. But that was wrong. Then, just messing a little, I let r=1 and then found t. t=1/3, which is correct. But how so? There is nothing to indicate that r was 0.5. I'm not sure of the logic....could anyone explain? Thanks!


Bolded
Original post by marcsaccount
Hi,

I got the right answer with this question, but only by messing around with it and not really understanding the logic behind what I was doing. Could anyone explain why what I did gave the correct answer..it really doesn't make sense to me.

The radius, r cm, of a circular ink spot, t seconds, after it first appears, is given by:

r=1+4t2+t \frac{1+4t}{2+t} The initial size is found by letting t=0.

Calculate the time taken for the radius to double its initial size.

So, initially I thought to double the RHS as the radius has doubled. But that was wrong. Then, just messing a little, I let r=1 and then found t. t=1/3, which is correct. But how so? There is nothing to indicate that r was 0.5. I'm not sure of the logic....could anyone explain? Thanks!

If the initial size is when t=0, then r at t=0 is clearly 0.5 if you sub in t=0. Double this would obviously be 1. So shouldn't you just set it equal to 1 and rearrange for t? No need for differentiation..
(edited 10 years ago)
Reply 3
thanks - makes sense :wink:

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