suggest the formula for sodium chlorate (VII)?

Watch
games211
Badges: 16
Rep:
?
#1
Report Thread starter 6 years ago
#1
How do you work this out, please?
Quote me
0
reply
zed963
  • Study Helper
Badges: 16
Rep:
?
#2
Report 6 years ago
#2
(Original post by games211)
How do you work this out, please?
Quote me
Isn't it NaClO?
0
reply
games211
Badges: 16
Rep:
?
#3
Report Thread starter 6 years ago
#3
(Original post by zed963)
Isn't it NaClO?
no
0
reply
alow
Badges: 19
Rep:
?
#4
Report 6 years ago
#4
(Original post by zed963)
Isn't it NaClO?
No.

The chlorate ion has an oxidation no. of -7, so what do you think it will be?
0
reply
darkred
Badges: 20
Rep:
?
#5
Report 6 years ago
#5
(Original post by games211)
How do you work this out, please?
Quote me

oxidation state of the chlorine is +7 because of the given (VII) which refers to the element with the variable oxidation state which in this case i Cl

so we know Na is +1, and that chlorate (Cl +O) is -1.

therefore we'd need 4 ClOs because the oxidation of the Cl is +7, and it needs to balance O is -2

+1 + 4(-2) = 0

Answer: NaClO4

I think
0
reply
zed963
  • Study Helper
Badges: 16
Rep:
?
#6
Report 6 years ago
#6
(Original post by alow)
No.

The chlorate ion has an oxidation no. of -7, so what do you think it will be?
How can that be possible? Don't you mean +7

If so +1 +7 -8

Therefore NaClO4

Na=+1
Cl=+7
O4=4(-2) = -8

Therefore its balanced.
0
reply
zed963
  • Study Helper
Badges: 16
Rep:
?
#7
Report 6 years ago
#7
(Original post by games211)
no
See post 6.
0
reply
games211
Badges: 16
Rep:
?
#8
Report Thread starter 6 years ago
#8
(Original post by failingatm)
oxidation state of the chlorine is +7 because of the given (VII) which refers to the element with the variable oxidation state which in this case i Cl

so we know Na is +1, and that chlorate (Cl +O) is -1.

therefore we'd need 4 ClOs because the oxidation of the Cl is +7, and it needs to balance O is -2

+1 + 4(-2) = 0

Answer: NaClO4

I think
How do you know that the ox number refers to chlorine, I don't really understand the variable bit.
0
reply
darkred
Badges: 20
Rep:
?
#9
Report 6 years ago
#9
(Original post by games211)
How do you know that the ox number refers to chlorine, I don't really understand the variable bit.
because group 1 elements are always +1 and group 2 always +2

Oxygen is always -2 except in peroxides

Cl is USUALLY -1 except when in compounds with F or O... so we have here NaClO - it is with Oxygen. So it has to be the variable element.

http://www.chemguide.co.uk/inorganic...idnstates.html more info.

you just have to look at the compound as a whole and deduce it.
0
reply
bobbricks
Badges: 19
Rep:
?
#10
Report 6 years ago
#10
sodium chlorate (VII) is NaClO4 .The VII bit indicates that the Chlorine has an oxidation number of +7 ,as one oxygen atom would always have an oxidation number -2. The sodium has an oxidation number of +1 since it's a group 1 element.

So we have:
Na- 1+
Cl- 7+
O- ?
How many oxygens do we need to balance out the +8 charge? We need 4 oxygens (as 4x-2=-8) so the formula is NaClO4
0
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts
Back
to top
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

Do you have the space and resources you need to succeed in home learning?

Yes I have everything I need (91)
65%
I don't have everything I need (49)
35%

Watched Threads

View All
Latest
My Feed