# suggest the formula for sodium chlorate (VII)?

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#1
How do you work this out, please?
Quote me
0
6 years ago
#2
(Original post by games211)
How do you work this out, please?
Quote me
Isn't it NaClO?
0
#3
(Original post by zed963)
Isn't it NaClO?
no
0
6 years ago
#4
(Original post by zed963)
Isn't it NaClO?
No.

The chlorate ion has an oxidation no. of -7, so what do you think it will be?
0
6 years ago
#5
(Original post by games211)
How do you work this out, please?
Quote me

oxidation state of the chlorine is +7 because of the given (VII) which refers to the element with the variable oxidation state which in this case i Cl

so we know Na is +1, and that chlorate (Cl +O) is -1.

therefore we'd need 4 ClOs because the oxidation of the Cl is +7, and it needs to balance O is -2

+1 + 4(-2) = 0

I think
0
6 years ago
#6
(Original post by alow)
No.

The chlorate ion has an oxidation no. of -7, so what do you think it will be?
How can that be possible? Don't you mean +7

If so +1 +7 -8

Therefore NaClO4

Na=+1
Cl=+7
O4=4(-2) = -8

Therefore its balanced.
0
6 years ago
#7
(Original post by games211)
no
See post 6.
0
#8
(Original post by failingatm)
oxidation state of the chlorine is +7 because of the given (VII) which refers to the element with the variable oxidation state which in this case i Cl

so we know Na is +1, and that chlorate (Cl +O) is -1.

therefore we'd need 4 ClOs because the oxidation of the Cl is +7, and it needs to balance O is -2

+1 + 4(-2) = 0

I think
How do you know that the ox number refers to chlorine, I don't really understand the variable bit.
0
6 years ago
#9
(Original post by games211)
How do you know that the ox number refers to chlorine, I don't really understand the variable bit.
because group 1 elements are always +1 and group 2 always +2

Oxygen is always -2 except in peroxides

Cl is USUALLY -1 except when in compounds with F or O... so we have here NaClO - it is with Oxygen. So it has to be the variable element.

you just have to look at the compound as a whole and deduce it.
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6 years ago
#10
sodium chlorate (VII) is NaClO4 .The VII bit indicates that the Chlorine has an oxidation number of +7 ,as one oxygen atom would always have an oxidation number -2. The sodium has an oxidation number of +1 since it's a group 1 element.

So we have:
Na- 1+
Cl- 7+
O- ?
How many oxygens do we need to balance out the +8 charge? We need 4 oxygens (as 4x-2=-8) so the formula is NaClO4
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