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FP2 Further Complex Numbers Exercise 3F Q.16

I have attached the question and the solution. But, I don't understand part C!

Surely the maximum argument of z would be at the bottom of the circle. ( at -2, i(2sqroot3 -2))

Reply 1

UsamaS

Help me oh students please!

Reply 2

Angryification

z refers to the "magnitude" of z, not stationary points of the locus.. It's easier if you convert to a cartesian equations and then use vectors

Reply 3

Solivagant

Original post by UsamaS

I have attached the question and the solution. But, I don't understand part C!

Surely the maximum argument of z would be at the bottom of the circle. ( at -2, i(2sqroot3 -2))

That's what it is saying.

Reply 4

davros

Original post by UsamaS

I have attached the question and the solution. But, I don't understand part C!

Surely the maximum argument of z would be at the bottom of the circle. ( at -2, i(2sqroot3 -2))

The argument is measured from the positive x-axis (real axis). If you look at the diagram in the solution, you can see that the required point is NOT directly below the centre of the circle.