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A question on work in Edexcel Chapter 4, C1

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(edited 6 years ago)
Original post by Wisefire
Referring to Exercise 4E, Edexcel, Chapter 4, Page 59, I don't understand this:

If a transformation of f(x)+2 is done to the graph of f(x)=x^3 (meaning a vertical translation of +2), the new y-coordinate (of intersection) is (0,2). I get that.

But, the new x-coordinate (of the point of intersection), according to the mark scheme, is ((the cubed root of 2),0), or "((cubrt(2)), 0)". I can't really see why. I mean, I obviously get where that comes from. But could somebody explain/go through the process of deduction step by step?

Thanks.


Well you have the equation y=x^3 + 2

since it's the coordinate on the x axis then y=0

So you get x^3 + 2 = 0

I think that's right. Do you see where to go from there?
Reply 2
Original post by Wisefire
Bump... Desperate to get my head round this above ^


Well, 1- (x+1) is just -x isn't it? :smile:

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