# Algebraic Fractions

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#2

(Original post by

Simplify

Why does multiplying the fraction by 6 to get rid of the fractions in the denominator give the answer 6(x-1) and not (x-1).

Am I right to say I'm still correct by obtaining (x-1) as the answer since I multiplied each term in the numerator by 6 and then factorised the quadratic?

**Noah~**)Simplify

Why does multiplying the fraction by 6 to get rid of the fractions in the denominator give the answer 6(x-1) and not (x-1).

Am I right to say I'm still correct by obtaining (x-1) as the answer since I multiplied each term in the numerator by 6 and then factorised the quadratic?

How did you factorize?

Edit: No, you're wrong. You forgot a 6 in your second bracket. (3x+2)(x-1) clearly does not give 18x^2.

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#3

**Noah~**)

Simplify

Why does multiplying the fraction by 6 to get rid of the fractions in the denominator give the answer 6(x-1) and not (x-1).

Am I right to say I'm still correct by obtaining (x-1) as the answer since I multiplied each term in the numerator by 6 and then factorised the quadratic?

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#4

(Original post by

Am I right to say I'm still correct by obtaining (x-1) as the answer since I multiplied each term in the numerator by 6 and then factorised the quadratic?

**Noah~**)Am I right to say I'm still correct by obtaining (x-1) as the answer since I multiplied each term in the numerator by 6 and then factorised the quadratic?

You have not factorised the new quadratic

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(Original post by

18x^2 - 6x - 12 if you factorise it gives you 6(3x+2)(x-1) because if you expand (3x+2)(x-1) you get 3x^2 -x -2 so you just factorised it wrong

**Iowan**)18x^2 - 6x - 12 if you factorise it gives you 6(3x+2)(x-1) because if you expand (3x+2)(x-1) you get 3x^2 -x -2 so you just factorised it wrong

(Original post by

right?

How did you factorize?

Edit: No, you're wrong. You forgot a 6 in your second bracket. (3x+2)(x-1) clearly does not give 18x^2.

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**majmuh24**)right?

How did you factorize?

Edit: No, you're wrong. You forgot a 6 in your second bracket. (3x+2)(x-1) clearly does not give 18x^2.

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Posting this so you can confirm if I have the correct intuition behind this.

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#6

(Original post by

Factorising the new quadratic using the quadratic formula gives (when expanded this does not give the quadratic term factorised back). Does the quadratic formula assume ? Whereas, in our case the term is not equal to 0.

**Noah~**)Factorising the new quadratic using the quadratic formula gives (when expanded this does not give the quadratic term factorised back). Does the quadratic formula assume ? Whereas, in our case the term is not equal to 0.

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#7

**Noah~**)

Factorising the new quadratic using the quadratic formula gives (when expanded this does not give the quadratic term factorised back). Does the quadratic formula assume ? Whereas, in our case the term is not equal to 0.

The quadratic formula gives solutions - it does not factorise

I am sure that you know that

And that, in fact

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(Original post by

You seem very confused

The quadratic formula gives solutions - it does not factorise

I am sure that you know that

And that, in fact

**TenOfThem**)You seem very confused

The quadratic formula gives solutions - it does not factorise

I am sure that you know that

And that, in fact

I see where I went wrong and that was using the quadratic formula to factorise (like you said it does not factorise but give solutions).

Hence

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