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# IB Math Help Again.....PLS Watch

1. so i basically did this over and over again but i cant get the graph right as it shows in the calculator.
the problem is g(x) = 3x^2 / (x^2-3x-10)

so i found the intercepts, when x=o, y=0 and when y=0 , x=0
i found the vertcale and horizontale asymptotes
v.a = x=5 and x=-2
h.a. y=3

then using the quotient rule i found the stationary points:
x=0,y=o
and x=-20/9, y=0.13

and then i got some few points as x and put it into the orginal equation to find the y, so that plotting in the graph is more precise

however i cant get the graph (which has 3 lines) so i probably messing up in the calculations

pls help me and thanks
2. (Original post by sabi06)
then using the quotient rule i found the stationary points:
x=0,y=o
and x=-20/9, y=0.13
Your second stationary point should be at x=-20/3

however i cant get the graph (which has 3 lines) so i probably messing up in the calculations

pls help me and thanks

What part of the graph is causing problems?

It may help to rewrite the function and use polynomial division and partial fractions to break it up - possibly.
3. (Original post by ghostwalker)
Your second stationary point should be at x=-20/3

What part of the graph is causing problems?

It may help to rewrite the function and use polynomial division and partial fractions to break it up - possibly.
FHow can x be -20/3 because you simplify the dy/ex to -3x(9x+20)

and hpw hpw can it have 3 curves

1) the stationary points and intercepts
2) the points you choose as x and the You found y

4. (Original post by sabi06)
FHow can x be -20/3 because you simplify the dy/ex to -3x(9x+20)

Check the arithmetic that got you to that point. Should be -3x(3x+20)

and hpw hpw can it have 3 curves
It has three separate curves because the vertical asymptotes (2 of them) divide the real axis into three distinct portions.

1) the stationary points and intercepts
2) the points you choose as x and the You found y
Sorry, can't make sense of what you're saying/asking there.

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Updated: April 16, 2014
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