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# I need help with this BMAT question please Watch

1. I need help in the question number one in the attached file please
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2. 9322-specimen-section-1-.pdf (250.7 KB, 73 views)
3. P: (5*20)/2 = 50m
Q: 10*15 = 150m
R: 10*10= 100m
S: (10*20)/2 = 100m

So the answer is D (R and S).
P: (5*20)/2 = 50m
Q: 10*15 = 150m
R: 10*10= 100m
S: (10*20)/2 = 100m

So the answer is D (R and S).
Thank you very much
Sorry I dont' understand why you have divided for two in car P and S
5. (Original post by Leyslis)
Thank you very much
Sorry I dont' understand why you have divided for two in car P and S
It's a speed-time graph meaning the area under the line is the distance travelled. The area is a triangle meaning you divide by 2.

Q is also 75m, forgot to divide by 2.
It's a speed-time graph meaning the area under the line is the distance travelled. The area is a triangle meaning you divide by 2.

Q is also 75m, forgot to divide by 2.
I have understood now, thank you very much

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