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Differential Equations, Quick help needed. Watch

    • Thread Starter

    Hi, I've been set some differential coursework to do over Easter and I've found it fairly easy except I'm stuck at the very last bit.

    This Equation:

    (dv/dt)= -0.000858479v^2

    I solved to get :

    v= (0.000858479t+0.0104239)^(-1)

    By solving this equation i was able to plot a graph and compare it to the original data i was given.

    Now i have this equation for the second stage:

    (dv/dt)= -0.000858479v^(2)-2.51408

    And i need to be able to plot a graph for this so i can again compare it to the original data but i just can't get my head round it.

    Any quick help would be appreciated i need to send this of in the next couple days.

    Integral of 1/(1+x^2) is arctan x. You just need to rescale.
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