The Student Room Group
Competition - post a photo you've taken of nature >>
Competition - post a photo you've taken of nature >>
Competition - post a photo you've taken of nature >>

Components of velocity.

compon.png
The vertical component of the velocity at D is the same as the vertical component of the velocity at A.

Why is this? Wouldn't the vertical component of the velocity at D be 0 ms-1 Since it's no longer moving downwards?
Original post by BrokenS0ulz
compon.png
The vertical component of the velocity at D is the same as the vertical component of the velocity at A.

Why is this? Wouldn't the vertical component of the velocity at D be 0 ms-1 Since it's no longer moving downwards?


Should it not be the same magnitude, but in a different direction?

It is still moving downwards at D, it's after D that it stops moving down. If you have no problem with it moving upwards at A, you shouldn't have a problem with it moving downwards at D. It's the same sort of argument.
Reply 2
Avatar for BrokenS0ulz
BrokenS0ulz
OP
3
Original post by rayquaza17
Should it not be the same magnitude, but in a different direction?

It is still moving downwards at D, it's after D that it stops moving down. If you have no problem with it moving upwards at A, you shouldn't have a problem with it moving downwards at D. It's the same sort of argument.


Ok so D is just before the velocity becomes 0? That does explain why the vertical comp would be the same as it is in A. Thanks. :smile:
Reply 3
Avatar for alow
alow
19
Original post by BrokenS0ulz
Ok so D is just before the velocity becomes 0? That does explain why the vertical comp would be the same as it is in A. Thanks. :smile:


The vertical velocity after D will become zero, either indefinitely (if it slides along the ground) or instantaneously (if it bounces).

The vertical component of the velocity at D is not the same as at A, as velocity is a vector quantity and they are in different directions. It's the magnitude of the vertical velocity (or vertical speed) which is the same at A as D.
Original post by BrokenS0ulz
Ok so D is just before the velocity becomes 0? That does explain why the vertical comp would be the same as it is in A. Thanks. :smile:


Yeah. It's hard to get your head around at first!
Reply 5
Avatar for BrokenS0ulz
BrokenS0ulz
OP
3
Original post by alow
The vertical velocity after D will become zero, either indefinitely (if it slides along the ground) or instantaneously (if it bounces).

The vertical component of the velocity at D is not the same as at A, as velocity is a vector quantity and they are in different directions. It's the magnitude of the vertical velocity (or vertical speed) which is the same at A as D.


Thanks

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you