Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

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Maths Core 2 Trapezium Rule

0.5h(Y0+yn)+2(Y1+y2+.......+Yn-1) h=(b-a)/n

I've been trying to figure out how to do the trapezium rule for a while now!
Could anyone tell me what 'yn' means?
Thanks

Original post by boos63

0.5h(Y0+yn)+2(Y1+y2+.......+Yn-1) h=(b-a)/n

I've been trying to figure out how to do the trapezium rule for a while now!
Could anyone tell me what 'yn' means?
Thanks

It's easier to explain this with a diagram

Not that you will have "n" x values that would represent each of the strips that you've split your function into. So

y_1=f(x_1), y_2=f(x_2), ..., y_n=f(x_n)

OP

Original post by Slowbro93

It's easier to explain this with a diagram

Not that you will have "n" x values that would represent each of the strips that you've split your function into. So

y_1=f(x_1), y_2=f(x_2), ..., y_n=f(x_n)

thanks!
It's just in my formula given in the exam it uses the term 'yn' would that just be the number of trapeziums?

Original post by boos63

thanks!
It's just in my formula given in the exam it uses the term 'yn' would that just be the number of trapeziums?

I'll give you an example

Let

y=2x

If I have

x_1=1, x_2=2, ...x_n=n

Then I would have

y_1=2, y_2=4, ...y_n=2n

So

y_n

Would be the y value for a particular value x :yep:

:yep:

the y refers to the vertical measurements.

if you have n trapezia there are n + 1 vertical measurements required.

OP

Original post by the bear

the y refers to the vertical measurements.

if you have n trapezia there are n + 1 vertical measurements required.

Thanks!

:smile:

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