WinOrDie
Badges: 1
Rep:
?
#1
Report Thread starter 6 years ago
#1
Name:  20140426_212157.jpg
Views: 122
Size:  72.6 KB
How do u get from one step to the other??
My teacher explained but I forgot.
0
reply

rs232
Badges: 0
Rep:
?
#2
Report 6 years ago
#2
Any context? ie the question you're trying to answer
0
reply
james22
Badges: 16
Rep:
?
#3
Report 6 years ago
#3
If it is a + then it is obvious. If it is a - then x=-ln(c+\sqrt{c^2-1})=ln(\frac{1}{c+\sqrt{c^2-1}}).

Can you finish from here?

In future, you will likely get better responses by posting in the maths help forum.
0
reply
RVNmax
  • Study Helper
Badges: 18
Rep:
?
#4
Report 6 years ago
#4
EDIT: ignore this post! James 22 has pointed out that they are indeed equal.

(Original post by WinOrDie)
Name:  20140426_212157.jpg
Views: 122
Size:  72.6 KB
How do u get from one step to the other??
My teacher explained but I forgot.
I wouldn't say that is correct in general terms. - No link between them. Like the poster 'rs232' said, it might just be true in this question, so it would be good if you could post the question.
0
reply
james22
Badges: 16
Rep:
?
#5
Report 6 years ago
#5
(Original post by rs232)
Any context? ie the question you're trying to answer
Context does not matter.

(Original post by RVNmax)
I wouldn't say that is correct in general terms. - No link between them. Like the poster 'rs232' said, it might just be true in this question, so it would be good if you could post the question.
It is correct in general terms, provided c>=1.
0
reply
WinOrDie
Badges: 1
Rep:
?
#6
Report Thread starter 6 years ago
#6
(Original post by james22)
If it is a + then it is obvious. If it is a - then x=-ln(c+\sqrt{c^2-1})=ln(\frac{1}{c+\sqrt{c^2-1}}).

Can you finish from here?

In future, you will likely get better responses by posting in the maths help forum.
Yeah you got the assumptionI shoulda mentioned.
And nope I don't think I can go on from there :/
maybe ln(1)- ln(the rest)
0
reply
james22
Badges: 16
Rep:
?
#7
Report 6 years ago
#7
(Original post by WinOrDie)
Yeah you got the assumptionI shoulda mentioned.
And nope I don't think I can go on from there :/
maybe ln(1)- ln(the rest)
Try rationalising teh denominator, you will find that there is some convenient cancelling that occurs.
1
reply
WinOrDie
Badges: 1
Rep:
?
#8
Report Thread starter 6 years ago
#8
(Original post by james22)
Try rationalising teh denominator, you will find that there is some convenient cancelling that occurs.
aah thanks mate ofcourse difference of two squares
0
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts
Back
to top
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

Current uni students - are you thinking of dropping out of university?

Yes, I'm seriously considering dropping out (135)
14.61%
I'm not sure (40)
4.33%
No, I'm going to stick it out for now (280)
30.3%
I have already dropped out (24)
2.6%
I'm not a current university student (445)
48.16%

Watched Threads

View All