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Stuck on question? Enthalpy change
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#2
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#4
(Original post by iamspiderman)
Ok thanks
There is no mass given so would I need to divide the 2.00 mol dm-3 by the molar mass of cuso4 to get it?
Ok thanks
There is no mass given so would I need to divide the 2.00 mol dm-3 by the molar mass of cuso4 to get it?
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#6
for the experiment. You now need to work it out in terms of J/mol.
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#8
There was an excess of Mg, so you are limited by the amount of copper sulfate. How many moles of copper sulfate in 100 mL of 2.0 M solution?
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#10
Yes, 0.2 moles. Now just calculate how much heat would be released per mole of copper sulfate reacting.
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