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    first question:
    expand (3x-1)(2x+3)
    = 6x^2+7x-3
    then Im asked to show how I can use my answer to work out 29 * 23:
    how am I supposed to do that?
    Any help would be appreciated. Thanks In advance
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    (Original post by coatsoft)
    first question:
    expand (3x-1)(2x+3)
    = 6x^2+7x-3
    then Im asked to show how I can use my answer to work out 29 * 3:
    how am I supposed to do that?
    Any help would be appreciated. Thanks In advance
    I suspect a typo, and they really want 29 * 23.

    Looking at the factorisation, what might be a suitable choice for x?
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    (Original post by ghostwalker)
    I suspect a typo, and they really want 29 * 23.

    Looking at the factorisation, what might be a suitable choice for x?
    god been looking through my notes and had read a number wrong. My writings so bad. x = 10
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    (Original post by coatsoft)
    god been looking through my notes and had read a number wrong. My writings so bad. x = 10
    Yep. And just put that into the quadratic, which is easy to work out with x=10.
 
 
 
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