Stationary points Watch

Jimmy20002012
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I need help on this question, don't know where they get (0,2) from.

I have worked out that dy/dx = 96x + 128x^3=0

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It's part c


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Mr M
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(Original post by Jimmy20002012)
I need help on this question, don't know where they get (0,2) from.

I have worked out that dy/dx = 96x + 128x^3=0

Here is the question and mark scheme:

Name:  ImageUploadedByStudent Room1399837603.692900.jpg
Views: 83
Size:  81.2 KB
Name:  ImageUploadedByStudent Room1399837626.417273.jpg
Views: 69
Size:  87.6 KB

It's part c


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Put the value x=0 you found back into the equation to obtain the y value.
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shawn_o1
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The stationary point has x-coordinate 0; 0 is the only value of x that solves the equation 96x + 128x^3 = 0. Get the y-coordinate by using x = 0: y = (1 + 2(0))^4 + (1 - 2(0))^4
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