Back
to top
Titration problem
Watch this thread
Announcements
Page 1 of 1
Go to first unread
Skip to page:
m.maher
Badges:
0
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#1
If I have an unknown which has certain concentrations of Carbonate and biCarbonate ions. In addition, I have a ph.ph indicator and methyl orange indicator
-First of all, you used the ph.ph to titrate the unknown with HCL then the volume used from HCL (X) is equivalent to titrate half the concentration of carbonate ions.
-Secondly, you used methyl orange to titrate the same volume of the unknown with HCL and the volume used of HCL (Y) is equivalent to titrate all the concentrations of Carbonate and bicarbonate ions.
-you have molarity of HCL = M(HCl)
Calculate concentrations of carbonate M(CO3) and bicarbonate M(HCO3) ions in the unkown
My attempt :
After first titration :-
2X . M(HCl) = Volume of CO3 . M(CO3) = C
Now, I can get molarity of CO3 in sample and no. of moles of carbonate that titrated to bicarbonate (C)
After second titration :-
(Y-2x) . M(HCl) = C + number of moles of bicarbonate in unknown sample
Now, I can calculate number of moles of bicarbonate in unknown sample and divide it by volume so I can get its Molarity
IS THIS SOLUTION TRUE ??
__________________
-First of all, you used the ph.ph to titrate the unknown with HCL then the volume used from HCL (X) is equivalent to titrate half the concentration of carbonate ions.
-Secondly, you used methyl orange to titrate the same volume of the unknown with HCL and the volume used of HCL (Y) is equivalent to titrate all the concentrations of Carbonate and bicarbonate ions.
-you have molarity of HCL = M(HCl)
Calculate concentrations of carbonate M(CO3) and bicarbonate M(HCO3) ions in the unkown
My attempt :
After first titration :-
2X . M(HCl) = Volume of CO3 . M(CO3) = C
Now, I can get molarity of CO3 in sample and no. of moles of carbonate that titrated to bicarbonate (C)
After second titration :-
(Y-2x) . M(HCl) = C + number of moles of bicarbonate in unknown sample
Now, I can calculate number of moles of bicarbonate in unknown sample and divide it by volume so I can get its Molarity
IS THIS SOLUTION TRUE ??
__________________
0
reply
Borek
Badges:
4
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#2
Report
#2
(Original post by m.maher)
First of all, you used the ph.ph to titrate the unknown with HCL then the volume used from HCL (X) is equivalent to titrate half the concentration of carbonate ions.
First of all, you used the ph.ph to titrate the unknown with HCL then the volume used from HCL (X) is equivalent to titrate half the concentration of carbonate ions.
CO32- + H+ -> HCO3-
and not after
CO32- + 2H+ -> H2CO3
0
reply
m.maher
Badges:
0
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#3
I think that this question is very misleading too since half the concentration may means that it is used to titrate half the amount of carbonate to bicarbonate or it is used to do half the titration (All the carbonate to bicarbonate) but do you think my way of solving this problem is true if X is volume used to convert half the carbonate to bicarbonate ???
0
reply
Borek
Badges:
4
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#4
Report
#4
Your choice of symbols is rather unfortunate, as each time I look at the formulas I start to wonder concentration of what is denoted by C.
I think your second equation is wrong - Y-2X already takes care of the carbonate presence, so there is no need for C on the right.
But I can be wrong.
I think your second equation is wrong - Y-2X already takes care of the carbonate presence, so there is no need for C on the right.
But I can be wrong.
0
reply
vqFFq
Badges:
0
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#5
m.maher
Badges:
0
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#6
Let me express my solution a bit more :
C = no of moles of carbonate titrated to bicarbonate from the first titration
Y-2X = volume of HCL used to titrate (Bicarbonate in the sample + bicarbonate produced from titrated carbonate) That's why I added C moles with M(HCO3) . V(Sample)
C = no of moles of carbonate titrated to bicarbonate from the first titration
Y-2X = volume of HCL used to titrate (Bicarbonate in the sample + bicarbonate produced from titrated carbonate) That's why I added C moles with M(HCO3) . V(Sample)
0
reply
Borek
Badges:
4
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#7
Report
#7
(Original post by m.maher)
Y-2X = volume of HCL used to titrate (Bicarbonate in the sample + bicarbonate produced from titrated carbonate)
Y-2X = volume of HCL used to titrate (Bicarbonate in the sample + bicarbonate produced from titrated carbonate)
0
reply
X
Page 1 of 1
Go to first unread
Skip to page:
Quick Reply
