The Student Room Group

complexnumbers A2

ffff.png

I finished a,b(i) and half of (ii) I found p and q.no idea how to find alpha and beta...

Scroll to see replies

Reply 1
What is the maximum and minimum argument for a point in R? Draw an Argand diagram.
Reply 2
Original post by alow
What is the maximum and minimum argument for a point in R? Draw an Argand diagram.


You can give me more hints,but I doubt I'll understand.I'm really weak when it comes to arg 'things'...:frown:
Reply 3
Original post by economist2
You can give me more hints,but I doubt I'll understand.I'm really weak when it comes to arg 'things'...:frown:


Have you drawn the Argand diagram in part b)i)?

Do you know what arg(z)\text{arg}(z) means when you're looking at an Argand diagram?
Reply 4
Original post by alow
Have you drawn the Argand diagram in part b)i)?

Do you know what arg(z)\text{arg}(z) means when you're looking at an Argand diagram?


I drew it.The circle.
no,i dont know what the arg (z) means.
Reply 5
Original post by economist2
I drew it.The circle.
no,i dont know what the arg (z) means.


arg(z)\text{arg}(z) means the angle between the line connecting the origin to the point representing the complex number and the (z)\Re (z) axis, measured anticlockwise.
Reply 6
Original post by alow
arg(z)\text{arg}(z) means the angle between the line connecting the origin to the point representing the complex number and the (z)\Re (z) axis, measured anticlockwise.


Is it 45degrees or pi/4?
Reply 7
Original post by economist2
Is it 45degrees or pi/4?


No, that would be the argument of any point on the line connecting the origin and the centre of the circle. Think about the maximum and minimum arguments that any point in the circle could have.
Reply 8
Original post by alow
No, that would be the argument of any point on the line connecting the origin and the centre of the circle. Think about the maximum and minimum arguments that any point in the circle could have.


the top of the circle and the bottom of the circle?
The top would have coord. (4,6)
The bottom would have (4,2)

Is this what you meant?
Reply 9
Original post by economist2
the top of the circle and the bottom of the circle?
The top would have coord. (4,6)
The bottom would have (4,2)

Is this what you meant?


No. They wont be the points with the max/min arguments.

If you draw a line from the origin to the circumference of the circle, what's the biggest and smallest angles you can make (you'll have to draw some triangles for this).
Original post by alow
No. They wont be the points with the max/min arguments.

If you draw a line from the origin to the circumference of the circle, what's the biggest and smallest angles you can make (you'll have to draw some triangles for this).


tangents?
Reply 11
Original post by economist2
tangents?


Yep :smile:
Original post by alow
Yep :smile:

ah!finally!!! :biggrin: ......dont know what to do next...
Reply 13
Original post by economist2
ah!finally!!! :biggrin: ......dont know what to do next...


Draw some triangles with angles and side lengths that you know.
Original post by alow
Draw some triangles with angles and side lengths that you know.


ok.drew the triangle.base is the diameter of the circle right?do I find the angle at the tangent point or at the origin?
Reply 15
Original post by economist2
ok.drew the triangle.base is the diameter of the circle right?do I find the angle at the tangent point or at the origin?



Do it for one tangent at a time, then you get a right angle.
Original post by alow
Do it for one tangent at a time, then you get a right angle.


yeah got that.which angle is arg?
Reply 17
Original post by economist2
yeah got that.which angle is arg?


Between the point on the circumference, the origin and the x axis.
Original post by alow
Between the point on the circumference, the origin and the x axis.


ok,I got o.445 for alpha.but mark scheme says 0.424...what I do wrong?

think the m/s's wrong.
(edited 9 years ago)
Reply 19
Original post by economist2
ok,I got o.445 for alpha.but mark scheme says 0.424...what I do wrong?

think the m/s's wrong.


The MS is right.

Quick Reply

Latest