statistics dice and probability
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economist2
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How do I draw the table for this?Or is their a way to do without the table?
I know for two dice throws but this is three...
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the bear
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BabyMaths
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(Original post by economist2)
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How do I draw the table for this?Or is their a way to do without the table?
I know for two dice throws but this is three...
How do I draw the table for this?Or is their a way to do without the table?
I know for two dice throws but this is three...
I'm sure that you can fill in the rest.
FWIW I think that a tree diagram would be a horrible option.

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ghostwalker
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There're numerous ways to do it.
You could do a table assigning two of the dice to one axes. So, your column, for example, headings might be (1,1), (1,2), ... (4,4), with 64 cells in the table. It has the advantage that each cell will have the same probability.
Or, you could do a table for the sum of 2 dice, and then use that sum as the column headings for a second table. This would give 28 cells in your second table (+16 in the first), but each column would have different probabilities.
Or, as the bear suggested, a tree, but it would have 64 final branches!
Or, my preferred method.
List all possible outcomes, where the dice are sorted into descending order, e.g.
444,443,442,441,433, ..., 111. There are 20 possibilites. Work out the probability of each combination and the sum of the three dice, and add the probabilities for corresponding sums.
Or,....
You could do a table assigning two of the dice to one axes. So, your column, for example, headings might be (1,1), (1,2), ... (4,4), with 64 cells in the table. It has the advantage that each cell will have the same probability.
Or, you could do a table for the sum of 2 dice, and then use that sum as the column headings for a second table. This would give 28 cells in your second table (+16 in the first), but each column would have different probabilities.
Or, as the bear suggested, a tree, but it would have 64 final branches!
Or, my preferred method.
List all possible outcomes, where the dice are sorted into descending order, e.g.
444,443,442,441,433, ..., 111. There are 20 possibilites. Work out the probability of each combination and the sum of the three dice, and add the probabilities for corresponding sums.
Or,....
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