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Ka for a weak acid?

ImageUploadedByStudent Room1401012579.286856.jpgin the question it says that hno2 is a weak acid so WHY can't we write it as [H+]^2? I've always done that for weak acids :/


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It's because the concentration of H+ has a large component from water in a weak acid.

In neutral water, there are already some H+ ions. Say this amount is 'x'. A strong acid might release the equivalent of 10,000x - hence we ignore the contribution from water and say that 10,000 = 10,001 approximately. A weak acid might release only 5x ions. 5x = 6x is a much worse approximation, hence we can't say that the concentration of H+ is equal to the concentration of the NO2- ion.
Original post by rambo1168
ImageUploadedByStudent Room1401012579.286856.jpgin the question it says that hno2 is a weak acid so WHY can't we write it as [H+]^2? I've always done that for weak acids :/


Posted from TSR Mobile


If it gives you the acid then you write down [H+][A-] (in this case NO2-. It is just when you do the calculation you ASSUME [H+] = [A-] but if you are asked to write the Ka of a known acid you can and must put down the acid and its conjugate base.
Reply 5
[H+]2 is an approximation that works ONLY when:

1. You start with the solution of acid only (ie, the only source of A- is teh acid dissociation)

2. Amount of H+ from the acid dissociation is orders of magnitude higher than the amount of [H+]2 from the water autodissociation.

So in general it is wrong, it is OK only sometimes.

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