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Standard electrode potential HELP!

Hi, can someone solve this question from an Edexcel unit 5 past paper on standard electrode potential for me please? I am very confused!

Q: One of the components of rust found on objects made from iron, iron (III) hydroxide, Fe(OH)3. Use items 17, 19 and 44 from the standard electrode potential table in your data booklet, show how it is able to form in 2 steps, writing an equation for each step.

Item 17: Fe(OH)3, [Fe(OH)2 (s) + OH- (aq)] | Pt -0.56V
Item 19: Fe2+ (aq) | Fe (s) -0.44V
Item 44: [O2 (g) + 2H2O (l) ], 4OH- (aq) |Pt +0.40V

I've worked out the first equation is 2Fe (s) + O2 +2H2O -> 2Fe2+ + 4OH-
but how do you work out the 2nd equation?

Thanks!
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Original post by Furuba5
Hi, can someone solve this question from an Edexcel unit 5 past paper on standard electrode potential for me please? I am very confused!

Q: One of the components of rust found on objects made from iron, iron (III) hydroxide, Fe(OH)3. Use items 17, 19 and 44 from the standard electrode potential table in your data booklet, show how it is able to form in 2 steps, writing an equation for each step.

Item 17: Fe(OH)3, [Fe(OH)2 (s) + OH- (aq)] | Pt -0.56V
Item 19: Fe2+ (aq) | Fe (s) -0.44V
Item 44: [O2 (g) + 2H2O (l) ], 4OH- (aq) |Pt +0.40V

I've worked out the first equation is 2Fe (s) + O2 +2H2O -> 2Fe2+ + 4OH-
but how do you work out the 2nd equation?

Thanks!


Combine your equation with equation item 17

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