AQA Chemistry Unit 2 June 2014: Revision/Discussion/Exam Techniques Watch

santiago_carmelo
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Hello fellow Scientists and all. SO tomorrow is the Chemistry unit 2 exam for the AQA( that's all i know off)
Below are some helpful links to get you in the mood for some last minute revision before tomorrows big day:


http://alevelchem.com/aqa_a_level_ch...nit3.2/320.htm

http://www.thestudentroom.co.uk/wiki...emistry_Unit_2

http://www.a-levelchemistry.co.uk/


Discuss away my fellow people. Good Luck for Tomorrow. I know none of you will need it
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sofiamalik_1995
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(Original post by santiago_carmelo)
Hello fellow Scientists and all. SO tomorrow is the Chemistry unit 2 exam for the AQA( that's all i know off)
Below are some helpful links to get you in the mood for some last minute revision before tomorrows big day:


http://alevelchem.com/aqa_a_level_ch...nit3.2/320.htm

http://www.thestudentroom.co.uk/wiki...emistry_Unit_2

http://www.a-levelchemistry.co.uk/


Discuss away my fellow people. Good Luck for Tomorrow. I know none of you will need it
Aww thankyou good luck to you too


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TajwarC
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http://chemrevise.files.wordpress.co...hanisms-as.pdf Summary of all mechanisms !
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santiago_carmelo
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(Original post by TajwarC)
http://chemrevise.files.wordpress.co...hanisms-as.pdf Summary of all mechanisms !

You star woow. that's brilliant
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santiago_carmelo
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less that 3 hours to go guys.... whats an easier way to remember e-z isomerism
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RThornton
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Z=Zame(same) and therefore E must equal opposite
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Lol12
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How did you find it?
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santiago_carmelo
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(Original post by Lol12)
How did you find it?

wow that test got demolished

it was so goooood :cool:
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Lol12
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What did you write for the other way to make ethanol
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Stakesby
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Hydration of Ethene


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PeterPhan7
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Did anyone managed balance the equation?
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santiago_carmelo
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(Original post by PeterPhan7)
Did anyone managed balance the equation?

Yh i got
60,70,60,50, 40 i beleive.


i lost like 3 marks for that 1:10 ratio thing.. that made no sense at all
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Lol12
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It was 6 7 6 5 4
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PeterPhan7
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(Original post by santiago_carmelo)
Yh i got
60,70,60,50, 40 i beleive.


i lost like 3 marks for that 1:10 ratio thing.. that made no sense at all
For the 1:10 ratio question I put that there is a higher conc. of reactants so the forward reaction is favoured to get rid of reactant by producing more product. I think is is completely wrong because this only occurs when you increase the conc. of reactants when the reaction ha reached dynamic equilibrium.
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PeterPhan7
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(Original post by Lol12)
It was 6 7 6 5 4
Yeah, I'm gutted I loss out on that one mark, it's seem almost impossible to balance the oxygen but I did it again today and managed to get the right answer. Just a shame that it's a bit too late now...
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santiago_carmelo
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(Original post by PeterPhan7)
For the 1:10 ratio question I put that there is a higher conc. of reactants so the forward reaction is favoured to get rid of reactant by producing more product. I think is is completely wrong because this only occurs when you increase the conc. of reactants when the reaction ha reached dynamic equilibrium.
yh i spoke with my teacher she said that it shifts so you get more product. i completely misread the question. oswell

and for the balancing i hope they accept ratios
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Jessica Han
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(Original post by PeterPhan7)
Yeah, I'm gutted I loss out on that one mark, it's seem almost impossible to balance the oxygen but I did it again today and managed to get the right answer. Just a shame that it's a bit too late now...
Actually there is a balanced equation similar to it just below that one if you noticed, and I am pretty sure there's a reason for that to be there- it is a clue guys !

Usually people look at sulfate and balance both sides of it with same number, but in this particular one you have to add one on left hand side just as the 'clue' did.

I didn't get it the first time btw
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Jessica Han
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What did everyone put for the first question, 'marking the point where the equilibrium just starts'
I put X onto the horizontal axis corresponding to the place that both curves become a horizontal straight line. (Assuming that means the constant concentration), but some of my friends put where the lines cross, and I can't remember what the horizontal axis was so can't judge, the vertical axis was concentration by the way.
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santiago_carmelo
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(Original post by Jessica Han)
What did everyone put for the first question, 'marking the point where the equilibrium just starts'
I put X onto the horizontal axis corresponding to the place that both curves become a horizontal straight line. (Assuming that means the constant concentration), but some of my friends put where the lines cross, and I can't remember what the horizontal axis was so can't judge, the vertical axis was concentration by the way.

the cross was meant to be at the place where they entersected. since both sides of the equation eqaulled each other
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Stakesby
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(Original post by santiago_carmelo)
the cross was meant to be at the place where they entersected. since both sides of the equation eqaulled each other
The concentration at that point may be the same, but the rate of change of concentration (reaction rates) are different, where as when the lines level off the reaction rates are the same. And we all know the when in equilibrium, the forward reaction rate is equal to the backward reaction rate

As well as concentration is constant at equilibrium, which is shown when the level off. (Also a required condition when at equilibrium)

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